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adoni [48]
3 years ago
9

Todd and Tim are exercising. Todd does 20 push-ups at the same time as Tim does 30 push-ups. When Todd does

Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

50 pushups.

Step-by-step explanation:

simple pattern of adding 10 each time.

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Combine like terms to create an equivalent expression. Enter coefficients as simplified proper or improper fractions or integers
Art [367]

Answer:

Step-by-step explanation:

The first (and only step) is to remove the brackets.

-1/2 * - 3y = 3/2y       Two minus make a plus

-1/2 * 10 = - 5

Answer: 3/2 y - 5

8 0
3 years ago
What two numbers add to -26 and multiply to -56
sweet [91]

Answer:

-28 and 2

Step-by-step explanation:

3 0
3 years ago
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Sick-leave time used by employees of a firm in a course of one month has approximately normal distribution, with a mean of 200 h
Usimov [2.4K]

Answer:

a)0.62% probability that total sick leave for next month will be less than 150 hours.

b) 225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 200, \sigma = \sqrt{400} = 20

a.Find the probability that total sick leave for next month will be less than 150 hours.

This probability is the pvalue of Z when X = 150. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 200}{20}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062.

So there is a 0.62% probability that total sick leave for next month will be less than 150 hours.

b.In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

This is the value of X when Z has a pvalue of 0.90. So Z = 1.28

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 200}{20}

X - 200 = 20*1.28

X = 225.6

225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

6 0
4 years ago
38.5 is what percent of 72?​
lorasvet [3.4K]

Answer:

53.47

Step-by-step explanation:

6 0
3 years ago
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A single die is rolled twice. Find the probability of getting a 2 the first time and a 6 the second time. Express the probabilit
myrzilka [38]

it would be 2/6 bc, one die, rolled twice, and landing on a 2 the first time and 6 the second time, is actually a 2/6 chance, you have 6 numbers, one die, two chances.

3 0
3 years ago
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