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vodomira [7]
2 years ago
5

What is the area of the figure below?

Mathematics
2 answers:
mr_godi [17]2 years ago
8 0
The answerr is 12 square units
ololo11 [35]2 years ago
6 0
The answer is 12!

How do you get this answer?
start by counting the boxes there’s a total of six in the first rectangle and 6 on the other so 6+6= 12!!!
Just count the boxes and that’s it:)
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3 years ago
What is the third side of the triangle when the other two is 7 and 4
Diano4ka-milaya [45]

Answer:

sqrt. 65

Step-by-step explanation:

assuming that it is a right angle

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3 years ago
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Megan is sitting in her car in a parking lot. The car next to her pulls forward. If Megan is looking only at the car next to her
Zina [86]

Answer:Backward

Step-by-step explanation:

If the car next to Megan is being Pulled Forward and Megan is seeing only the pulled car then her car appears to be moving backward.

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Here Megan's car appears to move backward with respect to the car next to her due to the existence of relative velocity.

6 0
3 years ago
Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti
almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

d=v.t

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

d=(x+y).t_1

Where t1=2.5 hours. Substituting values:

20=(x+y)*2.5

Rearranging, we find the downstream equation:

2.5x+2.5y=20\qquad[1]

The speed when rowing upstream is x-y, and the distance traveled is

d=(x-y).t_2

Where t2=5 hours. Substituting values:

20=(x-y)*5

Rearranging, we find the upstream equation:

5x-5y=20\qquad[2]

Multiplying [1] by 2:

5x+5y=40

Adding this equation to [2]:

10x=60

Solving:

x=60/10=6

Dividing [2] by 5:

x-y=4

Solving for y

y=x-4=6-4=2

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0
4 years ago
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