<span>5×(2-x)+9-7x
=5</span>×2-5<span>×x+9-7x
=10-5x+9-7x
=10+9-(5x+7x)
=19-12x
That's your solution. ^_^</span>
That question is accompanied by these answer choices:
<span>A. The scale is accurate but not precise.
B. The scale is precise but not accurate.
C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.
Then you need to distinguish between accuracy and precision.
Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.
The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.
So, the answer is that the scale is precise but not accurate (the option B</span>
Answer:
(-infinity, infinity) or all real numbers
Step-by-step explanation:
Answer:
yes , 33^2 + 56^2 = 65^2 and obtuse
Step-by-step explanation:
<h2><u>Question 3</u></h2>
make use of the Pythagoras theorem
which is :
c^2 = a^2 + b^2
where c is the hypotenuse.
now put the values in the equation
65^2 = 56^2 + 33 ^2
the answer is :
<u>yes , 33^2 + 56^2 = 65^2</u>
<u></u>
<h2><u>Question 4</u></h2>
<u />
note if :
c^2 = a^2 + b^2 ----------- right
c^2 < a^2 + b^2------------ acute
c^2 > a^2 + b^2------------- obtuse
hence :
16 + 30 > 38
therefore its : <u>obtuse </u>
Answer:
IM struggling with the too D:
Step-by-step explanation:
