Answer:
it takes approximately 11 years and 3 months (11.4 years) for Belinda's investments to double.
Step-by-step explanation:
To calculate the time it takes for Belinda's money to double, we will use the simple interest formula as shown below:
Simple interest = P × R × T
where:
P = principal = $800
R = Rate in decimal = 8.75% = 0.0875
T = time = ???
simple interest = $800 ( her money doubles)
∴ 800 = 800 × 0.0875 × t
800 = 70 × t
∴ t = 800 ÷ 70 = 11.4 years. (11 years and 3 months)
Therefore after approximately 11 years and 3 months, Belinda's investments doubles
Answer:
$12320
Step-by-step explanation:
Given data
Cost of car= $17500
rate of depreciation= 11%
duration= 2003 - 2006= 3 years
Let us apply the compound interest formula
A= P(1-r)^t
Note the negative sign(this is because of the depreciation)
A=17500(1-0.11)^3
A= 17500(0.89)^3
A= 17500*0.704
A= $12320
Hence the value of the car is $12320
Step-by-step explanation:
81/5=3x
x=81×1/5×3
x=81/15
X = -7 y=-7 + 7
x = -5 1/2 y=-2(-5 1/2) - 11
