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KonstantinChe [14]
3 years ago
7

In the year 2003, a person bought a new car for $17500. For each consecutive year after that, the value of the car depreciated b

y 11%. How much would the car be worth in the year 2006, to the nearest hundred dollars?
Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

$12320

Step-by-step explanation:

Given data

Cost of car= $17500

rate of depreciation= 11%

duration= 2003 - 2006= 3 years

Let us apply the compound interest formula

A= P(1-r)^t

Note the negative sign(this is because of the depreciation)

A=17500(1-0.11)^3

A= 17500(0.89)^3

A=  17500*0.704

A= $12320

Hence the value of the car is $12320

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What is 7 im so confused
erastova [34]

Answer:

7 weeks

Step-by-step explanation:

John saves  f(x) = 60+5x

Sarah saves g(x) =x^2 +46

They save the same amount of money

Set the equations equal

60+5x =x^2 +46

Subtract 60 from each side

60+5x -60 =x^2 +46-60

5x= x^2 - 14

Subtract 5x from each side

5x -5x= x^2-5x - 14

0 = x^2-5x - 14

Factor

0 = (x-7) (x+2)

Using the zero product property

x-7=0   x+2 =0

x=7  x=-2

Since we cannot have negative weeks

x=7

5 0
3 years ago
1/3(3y-z) in distributive property​
Nostrana [21]

Answer:

1/3 × 3y - 1/3 × z

The drawing will help

8 0
3 years ago
The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure
Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?  

Use 3.14 to approximate π .  


Enter your answer in the box.  in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cylinder volume)

V = \pi *r^2*h

V = 3.14 *2.5^2*7

V = 3.14*6.25*7

V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{2.5^3}{3}

V = 2*3.14 * \dfrac{15.625}{3}

V = \dfrac{98.125}{3}

\boxed{ V_{hemisphere} \approx 32.70\:in^3}

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

5 0
3 years ago
Read 2 more answers
Help with these questions plzz 21,22,23 PLZZZ
vivado [14]
<h2>21.</h2>

Let x represent the original number of books (the value we're asked for by the problem question). Then after this number was doubled, its was 2x. After 4028 was added, it was 2x+4028. That value is given by the problem statement as being 51,514, so the equation can be ...

... 2x + 4,028 = 51,514

... 2x = 47,486 . . . . . . . . . . . subtract 4028

... x = 23,743 . . . . . . . . . . . . divide by 2

The library had 23,743 books before the transactions described.

<h2>22.</h2>

Let t represent the number of minutes required for you to finish. Then in t minutes, you have prepared 2t carrots. The number of carrots you need can be described by ...

... 2t + 18 = 60

... t + 9 = 30 . . . . . . divide by the coefficient of t

... t = 21 . . . . . . . . . . subtract 9

It will take you 21 minutes to finish.

<h2>23.</h2><h3>Given</h3>
  • cost is $39.95 plus $0.35 for each minute over 500
<h3>Find</h3>
  • cost as a function of the number of minutes usage over 500
  • the number of minutes over 500 for a bill of $69.70
<h3>Solution</h3>

Let m represent the number of minutes usage over 500. Let c(m) represent the cost as a function of m. The given relation can be expressed as

... c(m) = 39.95 + 0.35m

We can substitute the bill information to find m:

... 69.70 = 39.95 + 0.35m

... 29.75 = 0.35m . . . . . . . . . subtract 39.95

... 85 = m . . . . . . . . . . . . . . . . divide by 0.35

The number of minutes over 500 for a bill of $69.70 is 85 minutes.

5 0
3 years ago
Round 0.9874 to the greatest non zero place
Anna71 [15]
0.9874 the greatest non zero place is 9 but the nearest digit is 8 when you round it off to 0.9 the answer becomes 1.0
0.9874~1.0
5 0
3 years ago
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