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xxTIMURxx [149]
3 years ago
14

Solve 12v^2 -9v=-2 in quadratic formula

Mathematics
1 answer:
andriy [413]3 years ago
3 0
Not sure what quadratic formula is but your answer is "No real Solutions"<span><span>
</span></span><span><span /></span>
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10) Solve using any method<br> 10x+2y=42<br> 5x+y=20
KIM [24]

Answer:

no solutions

Step-by-step explanation:

10x+2y=42

5x+y=20

Multiply the second equation by -2 to use elimination

-2(5x+y)=20*-2

-10x -2y = -40

Add this to the first equation

10x+2y=42

-10x -2y = -40

--------------------------

0 = 2

This is never true.  This means there are no solutions

3 0
3 years ago
Read 2 more answers
The answer to the problem
ser-zykov [4K]

Answer:

580

Step-by-step explanation:

4 0
3 years ago
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Can someone help me on this
fiasKO [112]

I know that i had it on a test its -2.11 Hope you ace it!

7 0
3 years ago
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15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
Read 2 more answers
What would my answer be?
Svetllana [295]
Since triangle is isosceles, that means that unknown angles are equal. 180-72=108
108:2=54
So you’re answer would be: 54 degrees.
4 0
2 years ago
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