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DENIUS [597]
3 years ago
7

Choose between ones that are slashed

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0
\textbf{You have to} restrict the domains of quadratic functions and absolute value functions, because these functions are \textbf{many-to-one} functions. For instance, the quadratic function f(x) = x^2 pairs both −2 and 2 with 4, and the absolute value function f(x) = |x| pairs both −2 and 2 with 2.

Linear functions (excluding constant functions) and exponential functions are \textbf{one-to-one} functions, so their domains \textbf{do not need} to be restricted.
_________________

An absolute value function, without domain restriction, has an inverse that is NOT a function.

In order to guarantee that the inverse must also be a function, we need to restrict the domain of the absolute value function to make it a one-to-one function.
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Answer:

Step-by-step explanation:

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3 years ago
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Answer: x=-10

Step-by-step explanation:

Let's solve your equation step-by-step.

6.2x+8=3(1.4x−4)

Step 1: Simplify both sides of the equation.

6.2x+8=3(1.4x−4)

6.2x+8=(3)(1.4x)+(3)(−4)(Distribute)

6.2x+8=4.2x+−12

6.2x+8=4.2x−12

Step 2: Subtract 4.2x from both sides.

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Step 3: Subtract 8 from both sides.

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Step 4: Divide both sides by 2.

2x2=−202

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9root (16)^3
= ∛16
= 2∛2

answer
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