Find the following for the function f(x) = |x| + 11.

A bike road race starts at an elevation of 920 feet and passes through 5 stages where the elevation changes by -559 feet, -100 f

Alenkasestr [34]

920 +(-559) +(-100) +(-441) +(175) +(-139)
=-144

The answer is E

7 0

3 years ago

(3, -5)(0, 4) Write the equation of a line using the point slope formula

Serga [27]

Answer:

y = - 3x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (3, - 5) and (x₂, y₂ ) = (0, 4)

m = $\frac{4-(-5)}{0-3}$ = $\frac{4+5}{-3}$ = $\frac{9}{-3}$ = - 3

The line crosses the y- axis at (0, 4) ⇒ c = 4

y = - 3x + 4 ← equation of line

7 0

2 years ago

Three friends go to the local framers market. Latasha spends $3.35. Helen spends 4 times as much as Latasha. Dee spends $7.50 mo

mylen [45]

Given:

Latasha spends $3.35

Helen spends 4 times as much as Latasha.

Dee spends $7.50 more then Helen.

To find:

The amount Dee spends.

Solution:

It is given that, Latasha spends $3.35.

Helen spends 4 times as much as Latasha.

So, Helen spends = 4 × $3.35

= $13.40

Dee spends $7.50 more then Helen.

Dee spends = $13.40+$7.50

= $20.90

Therefore, dee spends $20.90.

8 0

2 years ago

Slope Of (5,-5) and (-1,-5)

Alex777 [14]

$\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-5}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{5}}}\implies \cfrac{-5+5}{-6}\implies \cfrac{0}{-6}\implies 0$