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2 years ago

in slope intercept form, what is the equation of the line having a slope of 2 and passing through the point (6,24)?

Mathematics

2 answers:

mario62 [17]2 years ago

7 0

Answer:

y = 2x + 12

Step-by-step explanation:

Yanka [14]2 years ago

4 0

Answer: y = 2x + 12

Explanation: The slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. Substituting 2 for m, 6 for x, and 24 for y, we have 24 = 2(6) + b. Simplifying, we get that b = 12, so the equation is y = 2x + 12.

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Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile

mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40' [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

$\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}$

Taking last two ratio,

$\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}$

Putting the value of BC , AC ,∠A,∠B

$\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}$

$\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}$

≈734.106 miles

Therefore they are 734.106 miles apart.

3 0

3 years ago

Which expression has a value that is equivalent to the given expression when n = 8?

mrs_skeptik [129]

Q1.

Put the value of n = 8 to the expressions:

2n + 10 → 2(8) + 10 = 16 + 10 = 26

A: 3n → 3(8) = 24 ≠ 26

B: 2(n + 5) → 2(8 + 5) = 2(13) = 26 :)

C: n² + 5 → 8² + 5 = 64 + 5 = 69 ≠ 26

D: 10n + 2 → 10(8) + 2 = 80 + 2 = 82 ≠ 26

<h3>Answer: B: 2(n + 5)</h3>

Q2.

x = 3, y = 2

L = 5y² - 2x → L = 5(2)² - 2(3) = 5(4) - 6 = 20 - 6 = 14

R = x² + ... → R = 3² + ... = 9 + ...

A: x² + x → 9 + 3 = 12 NOT

B: x² + y → 9 + 2 = 11 NOT

C: xy → 9 + (3)(2) = 9 + 6 = 15 YES

D: 2y → 9 + (2)(2) = 9 + 4 = 13 NOT

5y² - 2x < x² + xy

L = 14, R = 15, L < R CORRECT

<h3>Answer: C: xy</h3>

Q3.

3 + 6² = 3 + 36 = 39

A: 3³ + 12 = 27 + 12 = 39 NOT

B: 5² + 4² = 25 + 16 = 41 > 39 YES

C: 2³ + 5² + 6 = 8 + 25 + 6 = 39 NOT

D: 2³ + 14 + 17 = 8 + 14 + 17 = 39 NOT

<h3>Answer: B: 3 + 6² < 5² + 4²</h3>

6 0

3 years ago

Find an equation for a tangent plane z=e-x2-y2 at the point (0,0,1).

Nadya [2.5K]

Answer: equation of the tangent plane is z = 1

Step-by-step explanation:

Given equation

z = e^(-x²-y²) at point (0,0,1)

now let z = f(x,y)

Δf(x,y) = [ fx, fy ]

= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))

now

Δf (0,0) = [ 0, 0 ] = [ a, b ]

equation of the tangent plane therefore will be

z - z₀ = a(x-x₀) + b(y-y₀)

z - 1 = 0(x-0) + 0(y-0)

z - 1 = 0 + 0

z = 1

Therefore equation of the tangent plane is z = 1

7 0

3 years ago

A line with a slope of 3 passes through the point (-1, 2).

Rom4ik [11]

Answer:

y - 2 = 3(x + 1)

y - 2 = 3x + 3

y = 3x + 5

Step-by-step explanation:

8 0

3 years ago

How many roots does the polynomial equation have?

erik [133]

answers

the answers is 6

3 0

3 years ago

in slope intercept form, what is the equation of the line having a slope of 2 and passing through the point (6,24)?​

in slope intercept form, what is the equation of the line having a slope of 2 and passing through the point (6,24)?