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maria [59]
3 years ago
14

Tell whether each question can be written in the form y = mx + b

Mathematics
1 answer:
Inessa [10]3 years ago
6 0
Tell whether each question can be written in the form y = mx + b
y = 8 - x^2 NO
y = 4 + x YES
y = 3 - 2x YES
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A rectangle has a length 6 meters longer than double the width. The perimeters is i44 meters. Find the dimensions of the rectang
Oksana_A [137]
Use the information to form an equation
x = width
x + 6 = length
perimeter = length + length + width + width
x + x + x + 6 + x + 6 = 44
4x + 12 = 44
4x = 32
x = 32/4
x = 8
width = 8 meters
length = 8 + 6 = 14 meters
8 0
3 years ago
Answer both and brainliest you will get
nekit [7.7K]

Answer:

1. The first one is 1/4

2. The 2nd one is 2/5

Step-by-step explanation:

This answer is right because I'm like that.

4 0
2 years ago
Read 2 more answers
The measure of angle 4 is 120°, and the measure of angle 2 is 35°. What is the measure of angle 5?
pickupchik [31]

If this was a triangle, the answer would be 35 degrees. Can you plz show a graph if you have one though?

8 0
3 years ago
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After adding an 8-pound box with 6 identical boxes, the box weighted 72 pounds. The equation is 6x + 8 = 72. What does X equal?
Marianna [84]

Answer: x = 10.6666666 or 10 2/3

Step-by-step explanation:

6x + 8 = 72

     - 8   -8

6x = 64

6x/6 = 64/6

x = 10.6666666 aka 10 2/3

8 0
3 years ago
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The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k
stepan [7]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.
8 0
3 years ago
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