Tell whether each question can be written in the form y = mx + b

Mathematics

1 answer:

Inessa [10]3 years ago

6 0

Tell whether each question can be written in the form y = mx + b
y = 8 - x^2 NO
y = 4 + x YES
y = 3 - 2x YES

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A rectangle has a length 6 meters longer than double the width. The perimeters is i44 meters. Find the dimensions of the rectang

Oksana_A [137]

Use the information to form an equation
x = width
x + 6 = length
perimeter = length + length + width + width
x + x + x + 6 + x + 6 = 44
4x + 12 = 44
4x = 32
x = 32/4
x = 8
width = 8 meters
length = 8 + 6 = 14 meters

8 0

3 years ago

Answer both and brainliest you will get

nekit [7.7K]

Answer:

1. The first one is 1/4

2. The 2nd one is 2/5

Step-by-step explanation:

This answer is right because I'm like that.

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2 years ago

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The measure of angle 4 is 120°, and the measure of angle 2 is 35°. What is the measure of angle 5?

pickupchik [31]

If this was a triangle, the answer would be 35 degrees. Can you plz show a graph if you have one though?

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3 years ago

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After adding an 8-pound box with 6 identical boxes, the box weighted 72 pounds. The equation is 6x + 8 = 72. What does X equal?

Marianna [84]

Answer: x = 10.6666666 or 10 2/3

Step-by-step explanation:

6x + 8 = 72

- 8 -8

6x = 64

6x/6 = 64/6

x = 10.6666666 aka 10 2/3

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3 years ago

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The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k

stepan [7]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.

8 0

3 years ago