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Ugo [173]
2 years ago
8

A pre-image and its image under a translation have the same orientation?

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
8 0

Answer:

In a translation, ALL of the points move the same distance in the same direction. A translation is called a rigid transformation or isometry because the image is the same size and shape as the pre-image.

Step-by-step explanation:

In addition, the corresponding segment sides of the pre-image and image are parallel.

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Can someone please tell me what 2 - 1 1/2 equals? Please answer quickly !!!
sergeinik [125]

the answer is 3/2 to this question

7 0
3 years ago
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Geometry The volume of a cube is related to the area of a face by the formula V= A2.
Mnenie [13.5K]

Given :

The volume of a cube is related to the area of a face by the formula V=A^2.

To Find :

The volume of a cube whose face has an area of 100 cm.

Solution :

Area is :

A = 100 cm.

Putting value of A in given equation of volume.

We get :

V=100^2\ cm^2\\\\V=10000\ cm^2

Therefore, volume of cube is 10000 cm².

Hence, this is the required solution.

4 0
3 years ago
Please explain and/or show your work!! :)
PolarNik [594]
\left[ \begin{matrix} 2 & a \\ -1 & -2 \end{matrix} \right] + \left[ \begin{matrix} b & 4 \\ -2 & 1 \end{matrix} \right]

This addition of matrices can be combined into one matrix.
To add matrices, add the corresponding components of each matrix.

After adding, we'll have the following

\left[ \begin{matrix} 2+b & a+4 \\ -3 & -1 \end{matrix} \right]

This matrix should be equal to the matrix on the right-hand side of the equation. This means that each corresponding component of this matrix and the other matrix should be equivalent.

This means that

2+b=1
AND
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3 0
3 years ago
Solve for g 3g-10=-45​
Goryan [66]

Answer:

g = -18.3

Step-by-step explanation:

3g-10=-45

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/3 (Divide by 3 to cancel out the 3)

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5 0
3 years ago
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A model for the density δ of the earth’s atmosphere near its surface isδ=619.09−0.000097pwhere p (the distance from the center o
natta225 [31]

Answer: 3.751*10^18kg

Step-by-step explanation:

δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.

Calculating the density of air at 5km above earth surface

P = 5000m + 6370000m = 6.375*10^6m

δ = 619.09 -(.000097* 6.375*10^6)

δ = 0.715kg/m^3 = density

Since Mass = density*volume...equ2

To calculate volume of air around the spherical earth at height 5km

V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6

Substituting R and r in equation 2 to solve for volume of air

V = 1.085*10^21 - 1.08*10^21

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Substituting δ and V into equation 2 to solve for mass of air

M = 0.715 * (5.25*10^18)

M = 3.751*10^18kg

8 0
3 years ago
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