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2 years ago

Unit 4: Congruent Triangles bimo Homework 5: Proving Triangles Congruent: SSS & SAS

Mathematics

1 answer:

emmainna [20.7K]2 years ago

3 0

Answer:

SSS:

Draw a triangle with sides of 2 cm, 3cm and 4cm and another one of 4cm, 6cm and 8 cm. Both will be SSS congruent.

SAS:

Draw a triangle with sides of 2 cm, 3 cm and another side of your choice. The angle between sides of 2 and 3 cm is 30 degrees. Now draw a triangle with sides of 4 cm, 6cm and another side of your choice (but this one cannot be the double of the 3rd side of the first triangle!) . The angle between the sides of 4 cm and 6 cm should be 60 degrees. Now you have 2 SAS congruent triangles.

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Find the 97th term of the arithmetic sequence

kozerog [31]

<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1 = 25

The difference between two terms, d = 29 - 25 = 4

To find the 97th term,

By formula, $a_{n} = a_{1} + (n - 1) d$

Substituting the values in the above equation, we get

$a_{97} = 25 + (97 - 1) 4$

= 25 + (96 * 4)

= 25 + 384

= 409

The 97 th term in the given sequence is 409.

3 0

2 years ago

The graph of f(x) = 24x^2 + 63x +34/ 4x + 3 has an oblique asymptote at y =

g100num [7]

<em>Correct answer is C). 6X+11</em>

Step-by-step explanation:

The given function f(x)= $\frac{24x^{2} +63x + 34 }{4x+3}$

On simplying the function f(x),

f(x)= $\frac{6x(4x+3) -18x +63x + 34 }{4x+3}$

f(x)= $\frac{6x(4x+3) +45x + 34}{4x+3}$

f(x)= $\frac{6x(4x+3) +11(4x+3)+x-33 + 34 }{4x+3}$

f(x)= $\frac{6x(4x+3) +11(4x+3)+x+1}{4x+3}$

f(x)= $(6x+11)+\frac{(x+1)}{4x+3}$

From above equation

"(6x+11)" is Oblique asymptote and $\frac{(x+1)}{4x+3}$ is vertical asymptote

Therefore, Correct answer is C). 6X+11

8 0

3 years ago

Read 2 more answers

Brianne's town is building a pool based on a scale drawing that is 20 centimeters by 10 centimeters and uses the scale 1 cm:250

kiruha [24]

Answer:

$A=1250m^2$

Step-by-step explanation:

From the question we are told that

Dimension of drawing

20 centimetres by 10 centimetres

Scale of drawing

1 cm:250 cm

Generally the the Main dimension of the pool is mathematically given as

$L=length\ of\ scaled\ pool*250 cm\\B=length\ of\ scaled\ pool*250 cm\\L=20*250=5000 cm=50m\\B=10*250=2500 cm=25m$

Therefore Area Aof main pool is mathematically given as

$A=50m*25m=1250 m^2$

$A=1250m^2$

4 0

2 years ago

A quadrilateral has angles that measure 60°, 95°, and 150°.

Nikolay [14]

The sum of angles in a quadrilateral = 360 degrees.

Let the fourth angle be x:

Therefore: 60 + 95 + 150 + x = 360

305 + x = 360

x = 360 - 305

x = 55

Option B. I hope this helps.

6 0

3 years ago

susan figure the slope of the line passing through the points (4,19) amd (7,28) to be 1/3. the teacher believes susan is wrong.

melamori03 [73]

For (x1,y1) and (x2,y2)
slope=(y2-y1)/(x2-x1)

(4,19)
(7,28)

slope=(28-19)/(7-4)=9/3=3/1=3
because math

7 0

2 years ago