Question

To solve 49^3x = 343^2x+1, write each side of the equation in terms of base

Answer 1

Answer:

B : (7^2)^3x = (7^3)^2x+1

Step-by-step explanation:

Just did it on edge

Answer 2

Answer: $(7)^(^6^x^)=(7)^(^6^x^+^3^)$

Step-by-step explanation:

$49^3^x=343^2^x^+^1$

$(7^2)^(^3^x^)=(7^3)^(^2^x^+^1^)$

$(7)^(^6^x^)=(7)^(^6^x^+^3^)$

Up to this points, is the equation in terms of base, from now on, I'm going to try to solve it.

Since we have the same base, exponents must be equal

$6x=6x+3\\6x-6x=3\\0=3$

Since we lost our variable, there's nothing to solve for. Therefore, this has no solution.