3 years ago

(3x-8)(x + 2) = 2x2

1 answer:

4 0

3x(x+2)-8(x+2)=4
3x^2+6x-8x-17=4
3x^2-2x-21=0
3x^2-9x+7x-21=0
3x(x-3)+7(x-3)=0
(x-3)(3x+7)=0
Either
x-3=0
x=3
Or
3x+7=0
x=-7/3

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(3x-8)(x + 2) = 2x2​