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3 years ago

The number of text messages (t) that katie sends depends on the number of days (d) she is on vacation. the equation is t=50d+20.

1 answer:

3 0

Based on the equation katie gets 20 text messages + 50 more for each day she is away.
therefore the number 50 shows how much the number of text messages (t) increases for each day she is away.

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Write the number as a question of integers to show that it is rational.<br> Please reply quickly!

snow_lady [41]

Answer:

$\frac{-37}{99}$

Step-by-step explanation:

0.555555... becomes $\frac{5}{9}$

Using this logic, we can do the following:

$-0.37373737... = \frac{-37}{99}$

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

3 0

3 years ago

Please help this is really hard

DedPeter [7]

The answer is 125,000,000

Have a great day!

5 0

3 years ago

Zen rolled a fair six-sided die 12 times. The table below shows the number of times each number was rolled:

Sunny_sXe [5.5K]

4 was rolled 2 times
5 also 2 times
6 was rolled 4 times
So the result was greater than three eight times out of 12 rolls.
P=8/12=2/3

8 0

3 years ago

The cowboy rode into town on friday stayed there for 3 days and left on friday how can that be

fgiga [73]

His horse's name is Friday.

6 0

4 years ago

Read 2 more answers

Given the following information about a hypothesis test of the difference between two means based on independent random samples,

HACTEHA [7]

Answer:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

Step-by-step explanation:

Data given:

$n_1 =13$ represent the sample size for group 1

$n_2 =10$ represent the sample size for group 2

$\bar X_1 =12$ represent the sample mean for the group 1

$\bar X_2 =9$ represent the sample mean for the group 2

$s_1=5$ represent the sample standard deviation for group 1

$s_2=3$ represent the sample standard deviation for group 2

We are assuming two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The pooled variance is given by:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

4 0

3 years ago