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Darya [45]
3 years ago
9

Index and laws evaluate A) 55^0 B)100^1

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
5 0

Answer:

Step-by-step explanation:

Hey there!

so answer for (A is 1)

Answer for (B is 100)

Thank you have fun!

Serggg [28]3 years ago
5 0

Answer:

Step-by-step explanation:

a) 55^{0} = 1

Anything raised to power 0 is 1

b) 100^{1} =100

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When x+2 = 1/5y is written in standard form, what is the value or B
Ket [755]

Answer:

B=-1

Step-by-step explanation:

Standard form is Ax+By=C.

In this case, Ax is x, By is 1/5y, and C is +2.

To isolate the 2 (the C), subtract x from both sides of the equation:

x+2=1/5y

-x     -x

2=-x+1/5y.

Now, the value of B, the x value, is -1.

4 0
3 years ago
Fencing encloses a rectangular backyard that measures 300 feet by 600 feet. A blueprint of the backyard is drawn on the coordina
liubo4ka [24]

Answer:

(x-15)^2+(y-30)^2=36

Step-by-step explanation:

we know that

The dimensions of the rectangular backyard in the actual are 300 feet by 600 feet

The dimensions of the rectangular backyard in the blueprint are 30 units by 60 units

therefore

If the radius of the circular flower garden in the actual is 60 feet

then

the radius of the circular flower garden in the blueprint is 6 units

Find the center of the radius in the blueprint

Remember that the circular flower garden is in the center o the backyard

so

To find out the center, determine the midpoint of the rectangular backyard

C((0+30)/2,(0+60)/2)

C(15,30)

The equation of a circle in center radius form is equal to

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center

r is the radius

we have

(h,k)=(15,30)\\r=6\ units

substitute

(x-15)^2+(y-30)^2=6^2

(x-15)^2+(y-30)^2=36

4 0
4 years ago
What’s the slope ?Or is it undefined ?
stellarik [79]
The answer to your question is 6 and no it is not undefined
4 0
4 years ago
Please help me with this one question, and I'll upvote the brainliest answer
ra1l [238]

Answer:   " x = 12 " .

________________________________________________

Step-by-step explanation:

________________________________________________

<u>Note</u>: If 2 (two) triangles are "similar" ;  then their corresponding sides are "proportional".

________________________________________________

Since one of the sides [the "hypotenuse"] of one the triangles given ; shows the measurement containing an expression with a value of "x" — specifically;  " 6x + 28 " ;  

    →  And since we want to solve for the value of "x" ;  we  use this "hypotenuse" of said particular triangle to set up a "proportion" with corresponding sides; so we can solve for "x" :

→  Set up proportions as a "ratio" ; or fraction:

       →  7:28::25:(6x + 28) ;  Solve for "x" ;

Let us write this in the form of a "fraction" :

      →  \frac{7}{28} = \frac{25}{(6x+28)} ;

________________________________________________

<u>Note</u>:  

        →  Rewrite:  " \frac{7}{28} " ; by simplifying to:

                                    " \frac{1}{4} " ;

________________________________________________

         →  Since:  " \frac{7}{28} " ;

              =  " (7÷7) / (28÷7) " ;

              =  " (1 /4) " ;

              =   " \frac{1}{4} " .

________________________________________________

Now, rewrite the "proportion" ; as follows:

________________________________________________

        \frac{1}{4} = \frac{25}{(6x+28)}  ;

________________________________________________

Now:   "Cross multiply" ;  that is:

______________________________________

→   Given:   " \frac{a}{b} = \frac{c}{d} " ;  

         and:  " b\neq0 " ;  " d\neq0 " ;

→  Then:   " a * d "  =  " b * c " .

________________________________________________

Likewise:   " 1(6x + 28)  =  (4) * (25) "   ;

______________________________________________

SImplify:    " 6x + 28 =  100 " ;  Solve for "x" ;

→ Subtract "28" from each side of the equation:

                  →   " 6x + 28 - 28 = 100 - 28 "  ;

    to get:   →   " 6x  =  72  "  ;

Now, divide each side of the equation by:  " 6 " ;

        to isolate "x" on one side of the equation; & to solve for "x" ; as follows:

   →   "  6x  =  72  "  ;

         →   6x / 6  =  72 / 6 ;

  to get:

         →   " x  = 12 "  ;

        →   which is the answer.

______________________________________________

Hope this helps!

  Best wishes in your academic pursuits

          — and within the "Brainly" community!

______________________________________________

5 0
3 years ago
PLEASE HELP IM SO CONFUSED!!!
Step2247 [10]

Problem 1

The median weight of the Welsh corgis is 27 pounds. This is found in the table in row 1, column 2. Recall that the median is the middle most value, so that means 50% of the Welsh corgi weights will be less than 27 pounds, and also 50% of the weights are greater than 27 pounds.

========================================================

Problem 2

The Welsh corgis have the greater variation in weights. Why is this? There are two pieces of evidence:

The first of which is that the range for the first row (7) is larger than the range in the second row (2). The range is the difference between the max and min. The larger the range, the more spread out the data set will be.

The second piece of evidence is that the MAD (mean absolute deviation) for the Welsh corgis is larger compared to the MAD for the cocker spaniels group. The MAD is another way to measure the spread of a data set. Like the range, the larger the MAD gets, the more spread out the data is. It measures how far on average any given value is from the mean. It's similar to the standard deviation and variance, which are also measures of spread.

========================================================

Problem 3

Both dog breeds have the same mean value, and roughly the same median. Both the mean and median are measures of center. Based on just these two pieces of info alone, we could easily conclude that both dog groups have the same distribution more or less. Furthermore, we could conclude that both groups have roughly the same max weight value.

However, we discussed in problem 2 that the first group (Welsh corgi) is more spread out, so it's likely that could heavily imply that the min and max values are further from the center compared to the second group of dogs. Having a larger max would then mean that the corgi group has the largest weight.

In short, the answer is "Welsh corgi" due to this group having a greater spread, and that pushes the max further away from the center.

7 0
3 years ago
Read 2 more answers
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