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dalvyx [7]
3 years ago
13

Please help me with this one question, and I'll upvote the brainliest answer

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer:   " x = 12 " .

________________________________________________

Step-by-step explanation:

________________________________________________

<u>Note</u>: If 2 (two) triangles are "similar" ;  then their corresponding sides are "proportional".

________________________________________________

Since one of the sides [the "hypotenuse"] of one the triangles given ; shows the measurement containing an expression with a value of "x" — specifically;  " 6x + 28 " ;  

    →  And since we want to solve for the value of "x" ;  we  use this "hypotenuse" of said particular triangle to set up a "proportion" with corresponding sides; so we can solve for "x" :

→  Set up proportions as a "ratio" ; or fraction:

       →  7:28::25:(6x + 28) ;  Solve for "x" ;

Let us write this in the form of a "fraction" :

      →  \frac{7}{28} = \frac{25}{(6x+28)} ;

________________________________________________

<u>Note</u>:  

        →  Rewrite:  " \frac{7}{28} " ; by simplifying to:

                                    " \frac{1}{4} " ;

________________________________________________

         →  Since:  " \frac{7}{28} " ;

              =  " (7÷7) / (28÷7) " ;

              =  " (1 /4) " ;

              =   " \frac{1}{4} " .

________________________________________________

Now, rewrite the "proportion" ; as follows:

________________________________________________

        \frac{1}{4} = \frac{25}{(6x+28)}  ;

________________________________________________

Now:   "Cross multiply" ;  that is:

______________________________________

→   Given:   " \frac{a}{b} = \frac{c}{d} " ;  

         and:  " b\neq0 " ;  " d\neq0 " ;

→  Then:   " a * d "  =  " b * c " .

________________________________________________

Likewise:   " 1(6x + 28)  =  (4) * (25) "   ;

______________________________________________

SImplify:    " 6x + 28 =  100 " ;  Solve for "x" ;

→ Subtract "28" from each side of the equation:

                  →   " 6x + 28 - 28 = 100 - 28 "  ;

    to get:   →   " 6x  =  72  "  ;

Now, divide each side of the equation by:  " 6 " ;

        to isolate "x" on one side of the equation; & to solve for "x" ; as follows:

   →   "  6x  =  72  "  ;

         →   6x / 6  =  72 / 6 ;

  to get:

         →   " x  = 12 "  ;

        →   which is the answer.

______________________________________________

Hope this helps!

  Best wishes in your academic pursuits

          — and within the "Brainly" community!

______________________________________________

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So, 11/40ths is already in simplest form.

Hope I helped ya!! xD<span />
5 0
4 years ago
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dolphi86 [110]

Step-by-step explanation:

Howdy, did you do a, b, and c by yourself? Because there are some slight issues, so I'll do my best to explain.

a. 3x+5x

We know that x=2, so we can substitute 2 in for x right now, or we can combine like terms.

3x and 5x both have the variable x so we can add them easily to get 8x. If you substitute in 2, you're just multiplying 8×2, which is 16.

b. 5z+4z+z

Again, since

we know that z=-3, we can substitute in now, or we can combine like terms first. 5z, 4z, and z all have the variable x, we addition is easy. 5+4+1=10, so you'll have 10z. Substitute in -3 for z, and you're just multiplying 10×-3=-30

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3

6 0
3 years ago
6. If you need to dissolve 8 tablets of active ingredient B, each containing 3 mg, in 15,750 mL, what is the ratio strength (w/v
Nuetrik [128]

Answer:

1 : 656250

Step-by-step explanation:

It is given that we need to dissolve 8 tablets of active ingredient B, each containing 3 mg, in 15,750 mL.

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Weight of each tablet = 3 mg

Total wight of tablets = 8 × 3 = 24 mg

Total volume = 15,750 mL.

1 mL = 1000 mg

Total volume = 15,750000 mg

We need to find the ratio strength (w/v).

Ratio=\frac{\text{Total wight of tablets}}{\text{Total volume}}

Ratio=\frac{24}{15,750000}

Ratio=\frac{1}{656250}​

Therefore, the ratio strength (w/v) is 1 : 656250.

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3 years ago
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kipiarov [429]

I think your question seems to be :-

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