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Novay_Z [31]
3 years ago
15

Pleaseeeeeee helpppppppp meeeee

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0
All are relations except for relation 3
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Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X
timama [110]

Circle A is missing, so i have attached it.

Answer:

∠XYZ = 35°

Step-by-step explanation:

We want to find the angle ∠XYZ in the image attached.

To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;

∠XYZ = ½(arc WZ - arc XZ)

From the image, arc WZ = 175° and arc XZ = 105°

Thus;

∠XYZ = ½(175 - 105)

∠XYZ = ½(70)

∠XYZ = 35°

5 0
3 years ago
Read 2 more answers
If x = 5 and 5 = y, then x = y
garri49 [273]
You are right. Transitivity means, that:
if a = b and b = c, then a = c
(here a = x, b=5 and c = y).
5 0
3 years ago
Given the equation square root of quantity 2x plus 8 end quantity equals 6, solve for x and identify if it is an extraneous solu
Alex_Xolod [135]

Answer:

Solution: x = 6

Step-by-step explanation:

Given equation is:

\sqrt{2x+8}=6

In order to solve the equation both sides will be squared

(\sqrt{2x+8})^{2} = (6)^2 \\2x+8 = 36\\2x = 36-8\\2x = 28\\x = 14

Verifying the solution

\sqrt{2(14)+8} = 6\\ \sqrt{28+8} = 6\\\sqrt{36} = 6\\6 = 6

3 0
3 years ago
Read 2 more answers
A boat travels 320 miles in 11 hours (with a constant speed), How much
Arada [10]

Answer: 4.2625

Step-by-step explanation:

11/320=x/124

11*124=320x

1364=320x

x=4.2625

Hopefully I was helpful!

3 0
3 years ago
I am have trouble with these x-intercepts. Please help me.​
kotegsom [21]

Answer:

  1. x=8, x=2
  2. no solution
  3. no solution

Step-by-step explanation:

For the equation ...

  y = a(x -h)² +k

you can find the x-intercepts by setting y=0 and solving for x.

  0 = a(x -h)² +k

  -k = a(x -h)² . . . . . . subtract k

  -k/a = (x -h)² . . . . . divide by a

  ±√(-k/a) = x -h . . . . take the square root

  h ± √(-k/a) = x . . . . add h . . . . this is the general solution

__

So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".

1.  x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8

2.  x = -3 ± √(-2) . . . . . . no solution; the roots are complex

3.  x = 5 ± √(-8/4) . . . . . no solution; the roots are complex

7 0
3 years ago
Read 2 more answers
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