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Given:
A jar of coins has 8 pennies, 5 nickels, 1 dime, and 7 quarters.
To find:
The probability of drawing a quarter, replacing it, and drawing another quarter.
Solution:
A jar of coins has 8 pennies, 5 nickels, 1 dime, and 7 quarters.
Total number of coins = 8+5+1+7 = 21
Probability of getting a quarter is
After drawing a quarter, we replaced it. So, the probability of getting quarter in second draw is the same and first one, .i.e., .
The probability of drawing a quarter, replacing it, and drawing another quarter is
Therefore, the required probability is .