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Vesna [10]
3 years ago
15

Please help very confusing

Mathematics
1 answer:
Naily [24]3 years ago
6 0
The value of x is 23 because BC and EF are equal
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using the midpoint formula find the coordinates of the midpoint 9f each sigment with end points (4,2),(-5,-1)​
exis [7]

Answer:

The midpoint of the segment is (-0.5,0.5).

Step-by-step explanation:

Midpoint of a segment:

The midpoint of a segment is given by the mean of its coordinates.

Segment with end points (4,2),(-5,-1)​

x-coordinates: 4 and -5

y-coordinates: 2 and -1

x-coordinate of the midpoint:

x = \frac{4-5}{2} = -\frac{1}{2} = -0.5

y-coordinate of the midpoint:

y = \frac{2-1}{2} = \frac{1}{2} = 0.5

The midpoint of the segment is (-0.5,0.5).

3 0
3 years ago
What’s the answer of value v?
kotykmax [81]

Answer:

v = 9

Step-by-step explanation:

6v - 4 = 50

6v = 54

v = 9

8 0
3 years ago
Can the distributive property be used to rewrite
Harman [31]

Answer:

I think No

Step-by-step explanation:

6 0
4 years ago
Solve the following proportion n/6=15/3
Natalka [10]

We can simplify 15/3 to 5.


N/6 = 5. Then multiply both sides of the equation by 6, giving us N = 30.



5 0
3 years ago
Suppose x, y and z are integers. Prove that, if 3x−y + 5z is even, then at least one of x, y or z is even.
Elden [556K]

Given:

x, y and z are integers.

To prove:

If 3x-y+5z is even, then at least one of x, y or z is even.

Solution:

We know that,

Product of two odd integers is always odd.          ...(i)

Difference of two odd integers is always even.          ...(ii)

Sum of an even integer and an odd integer is odd.      ...(iii)

Let as assume x, y and z all are odd, then 3x-y+5z is even.

3x is always odd.          [Using (i)]

5z is always odd.          [Using (i)]

3x-y is always even.       [Using (ii)]

(3x-y)+5z is always odd.       [Using (iii)]

3x-y+5z is always odd.

So, out assumption is incorrect.

Thus, at least one of x, y or z is even.

Hence proved.

4 0
3 years ago
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