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2 years ago

10

L 1.6.3 Quiz: Measurement and Units

1 answer:

TEA [102]2 years ago

8 0

I don’t know i need points sorry so sorry

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$(3, -4)=(x,y)\\y=3x+2\\\\m_1 =3\\In\: perpendicular\: line ;\\\\m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{3} \\m_2 = -1/3\\\\Substitute \:new\:values\:into\: ;y=mx+b\\\\-4 = -\frac{1}{3} (3) + b\\-4 = -1 +b\\-4+1 =b\\-3 =b\\Substitute \:new\:values\:into\: ;y=mx+b\\y =-\frac{1}{3}x -3$

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