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2 years ago

How would you answer 8 (4 + 2) im confused please help

Mathematics

2 answers:

CaHeK987 [17]2 years ago

8 0

Answer:

perethis first so 8 (4+2) would be 4+2=6+8=14

Step-by-step explanation:

Zina [86]2 years ago

6 0

You start by doing PEMDAS, parentheses, exponents, multiplication, division, addition, subtraction, so you would start by answering (4+2) which would be (6) and you keep it in the parentheses, so 8(6) so the answer would be 48!

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When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected

jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

$N=\frac{12.36}{0.03+0.55^t}$

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

$N=\frac{12.36}{0.33+0.55^0}$

$N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12$

A. Initially, there were 12 deer.

B. $N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380$

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. $N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410$

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

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3 years ago

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Answer:

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Answer:

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Answer:

Step-by-step explanation:

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Step-by-step explanation: Found the answer on Khan Academy.

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