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Nutka1998 [239]
3 years ago
13

Solve the equation: (5y + 2)(y - 3) = -13(2 + y)

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

2i

Step-by-step explanation:

Distribute:

(5y + 2)(y - 3)

5y^2-15y+2y-6

Which can be simplified into 5y^2-13y-6

Now the equation now looks like this: 5y^2-13y-6=-13(2+y)

For -13(2+y) multiply -13 with 2+y

Which is -26-13y

5y^2-13y-6=-26-13y

Simplify:

5y^2+20

Which can be simplified into 5(y^2+4)

y^2+4=0

y^2=-4

y=2i

Hope this helps!

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Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source. The total capacitive reactance is _____.
muminat

<u>Answer</u>-

<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>

<u>Solution-</u>

Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.

The effective/equivalent capacitance of the circuit is,

C=20+30=50\ mF

As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.

We know that,

X_c=\dfrac{1}{2\pi fC}

Where,

X_c = Capacitive Reactance (in Ω)

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Here given,

X_c = ??

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Putting the values in the formula,

X_c=\dfrac{1}{2\pi \times 400\times 50\times 10^{-6}}

X_c=\dfrac{10^{6}}{40000\pi}

X_c=7.96\ \Omega

Therefore, the total capacitive reactance of the circuit is 7.96 Ω.

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