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If you needed only 1 c of milk, what is your best choice at the grocery store? a quart container, a pint container, or a 1/2 gal

Lena [83]

What would be best to buy is the quart container

8 0

4 years ago

Solve for the value of each letter.

creativ13 [48]

Answer:

Step-by-step explanation:

1] 6x + 10 = 28 {subtract 10 from both sides}

6x + 10 -10 = 28 - 10

6x = 18 {Divide both sides by 6}

6x/6 = 18/6

x = 3

2] -2m - 4 = 8 {Add 4 to both side}

-2m - 4 + 4 = 8 + 4

-2m = 12 {Divide both sides by -2}

-2m/-2 = 12/-2

m = -6

3] x + x + 2x = 48 {add the like terms}

4x = 48 {divide both sides by 4}

4x/4 = 48/4

x = 12

4] 3y +4 +3y - 6 = 34 {add the like terms}

6y - 2 = 34 {Add 2 to both side}

6y - 2 + 2 = 34 +2

6y = 36 {divide both sides by 6}

6y/6 = 36/6

y = 6

5]9(w - 6) = 36 {divide both sides by 9}

[9(w - 6)]/9 = 36/9

w - 6 = 4 {Add 6 to both sides}

w - 6 + 6 = 4 + 6

w = 10

4 0

3 years ago

Read 2 more answers

What is the answer for 3632.1÷10

antoniya [11.8K]

I think it would be 363.21 because you are moving the digits down by 10

7 0

3 years ago

Read 2 more answers

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

4 years ago

What is the diameter of a circle with a circumference of 6π?

vivado [14]

Answer:

the diameter, d, must be 6

Step-by-step explanation:

Formula for circumference of a circle with diameter d is C = πd.

If C = 6π = πd, then the diameter, d, must be 6.

7 0

4 years ago

And, New innings hidjsjs. dbsjsjjz djskskkdjd ​

And, New innings hidjsjs. dbsjsjjz djskskkdjd