Answer:
The system of equations 8x-3y=10 and 16x-6y=22 has no solution
Step-by-step explanation:
When both of the above equations are put into standard form, you get ...
8x - 3y = 10
8x - 3y = 11
This is an "inconsistent" pair of equations. There are no values of x and y that can satisfy both equations, hence there is no solution.
Answer:
a = $13.5
Step-by-step explanation:
Let a = adult tickets
Let c = children tickets
Translating the word problem into an algebraic equation;
<u>For the Martinez family;</u>
2a + 3c = $60
<u>For the Wright family;</u>
3a + 5c = $95.5
Thus, the simultaneous equations are;
..........equation 1
.........equation 2
We would use substitution method to solve;
From equation 2, we make a the subject of formula;
3a = 95.5 - 5c
a = (95.5 - 5c)/3
<em>Substituting the value of "a" into equation 1, we have;</em>
2[(95.5-5c)/3] + 3c = 60
Multiplying all through by 3;
2(95.5 - 5c) + 9c = 180
191 - 10c + 9c = 180
191 - c = 180
c = 191-180
c = $11
To find the value of a;
2a +3c = 60
<em>Substituting the value of "c" into the equation, we have;</em>
a = $13.5
<em>Therefore, the cost of an adult movie ticket is $13.5. </em>
Answer:
Step-by-step explanation:
+ we have
[sin(x)]^2 + [cos(x)]^2 = 1
so [cos(x)]= 1- [sin(x)]^2 = 1- (1/2)^2 = 1- 1/4 = 3/4
Then cos(x) can take one of two values;
+ cos(x) =
then tan(x)= sin(x)/cos(x) = (1/2)/ () =
+ cos(x) = -
then tan(x)= sin(x)/cos(x) = (1/2)/ (- ) = -
Have a good day