You could multiply 1/4 by 3 and 1/6 by 2. You would get 3/12 and 2/12. The common denomonator is 12. 4 and 6 are both multiples of 12.
Answer:
Ball distance from ground = 74 feet
Step-by-step explanation:
Given function;'
h(t) = -167(t) + C
t = number of seconds
c = height of the bridge
Find:
Ball distance from ground
If,
c = 260-foot-high bridge
t = 2 seconds
Computation:
h(t) = -167(t) + C
h(2) = -167(2) + 260
h(2) = -334 + 260
h(2) = -74
Ball distance from ground = 74 feet
Y(initial) = 9
V(initial) = 168
V(final) = 0
g(accel-grav) = 32 (in feet per second
squared)
Use the following equation:
V(final) = V(initial) + a(t)
Since this object is moving straight up and
down, a = -32
Enter the knowns into the equation
0 = 168 - 32t
32t = 168
t = 168/9.8
t = 5.25
Now that you know the time it takes to
reach it's maximum, use the general
kinematics equation to solve for final
distance:
y(final) = y(initial) + V(initial)(t) + (1/2)a
(t²)
y(final) = 9 + 168(5.25) + (1/2)(-32)
(5.25²)
= 9 + 882 - 441
= 450 feet
-5 - 12 = -17
Starts at -5 degrees, then it drops another 12, so you subtract 12 from -5.
Answer:
x-4=19
Step-by-step explanation:
Hope that helps!
