Answer:
Increase in her mass = 3.472 kg
Her new mass = 46.872 kg
Step-by-step explanation:
Her original mass = 43.4 kg
Percentage increase in her mass = 8%
Increase in her mass = 8% of 43.4 kg
= 8/100 * 43.4 kg
= 0.08 * 43.4 kg
= 3.472 kg
Increase in her mass = 3.472 kg
b) Work out her new mass
Her new mass = Her original mass + Increase in her mass
= 43.4 kg + 3.472 kg
= 46.872 kg
Her new mass = 46.872 kg
The answer to you equation is Y=63/8
Answer:
assuming we are multiplying 1/7 * w then w = 7/2 or 3 and 1/2
Step-by-step explanation:
Paul: 140 + 12x
Jacklyn: 56 + 16x
Where x is how many practice sessions he had this season
"After how many more practices will Paul and Jacklyn have completed the same number of laps?"
This means what will x be if both equations are equal to each other
140 + 12x = 56 + 16x
Isolate x in one side by subtracting both sides by 12x
140 + 12x - 12x = 56 + 16x - 12x
140 = 56 + 4x
Subtract both sides by 56 to shift the 56 from the right side to the left side
140 - 56 = 56 - 56 + 4x
84 = 4x
Divide both sides by 4 to isolate x
84/4 = 4/4x
21 = x
x = 21
They'll have completed the same number of laps after 21 practices
Hope it helps :)
Branliest would be appreciated
While linear<span> equations are always straight, </span>nonlinear<span> equations often feature curves.</span>
