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Elza [17]
2 years ago
11

Guys I really need some help with this one!

Mathematics
1 answer:
nika2105 [10]2 years ago
7 0

Answer:

f( 1 ) = 3

Step-by-step explanation:

Given the linear function, f(x) = -4x + 7, we could easily find f( 1 ) by substituting the value of the input, x = 1, into the function.

f(x) = -4x + 7

f( 1 ) = -4( 1 ) + 7

f( 1 ) = -4 + 7

f( 1 ) = 3

Therefore, the output value is f( 1 ) = 3.

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Which set of ordered pairs is a function?
DochEvi [55]
A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate. An equation that produces such a set of ordered pairs defines a function. What is the catch? There can be at most one output for every input.
4 0
3 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
Find the midpoint on segment AB; A (0, 6), B (4, 2)
Bogdan [553]

Answer:

2,4

Explanation:

Because a midpoint is the middle of the line

8 0
3 years ago
Read 2 more answers
George is 6 feet tall and his shadow measured 8 feet long at noon. At the same time, a nearby flagpole cast a 40-foot shadow. Wh
mash [69]

Answer:

42 I think LOL

6 0
3 years ago
Helpppppp:((((((this is due tomorrow and I still didn’t turn it in. Pls help if you can and take ur time but pls don’t take too
Arlecino [84]
#3 is < , =, =
#6 4L= 4,000ml
9L= 9,000ml
6g=6000mg
5 0
2 years ago
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