Answer:
that a hard question
Step-by-step explanation:
i tried to use a calculator and graphs to solve it but I couldn't
<h2>
Answer:</h2>
<em><u>Distance of the farmer's rectangular field around the field = 74.46 m</u></em>
<h2>
Step-by-step explanation:</h2>
In the given question,
Length of the rectangular field, L = 20.33 m
Width of the rectangular field, W = 16.9 m
Now,
The area of rectangular field is given by,
The total distance around the rectangular field is,
Distance = Perimeter of the the rectangle.
Perimeter of rectangle = 2(Length + Width)
Perimeter = 2(20.33 + 16.9)
Perimeter = 2(37.23)
Perimeter = 74.46 m
So,
<em><u>Distance of the farmer's rectangular field around the field is = 74.46 m</u></em>
diameter is 15 meters then radius is 15/2 = 7.5 meters
so the amplitude is 7.5 m and height will oscillate with amplitude 7.5 m above and below the center.
midline of the oscillation will be 7.5 m
the wheel.take 8 minutes to complete revolution then it means the height will oscillate with a period of 8 minutes
The X coordinate has to be 0
Answer:
approximately 8.16 times
Step-by-step explanation:
