A = 1 , b =3.5 i need help quick

I’m doing my finals I need to finsih pls help

Citrus2011 [14]

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8 0

2 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

PLEAZE HELP IM FAILING THIS CLASS 9) The volume of a box is represented by x' +11x² + 20x – 32. The width of the box is x – 1, a

In-s [12.5K]

Answer:

Step-by-step explanation:

Volume of the box = x³ +11x² + 20x – 32 I think the ' is a typo for ³

the width is x-1 and the height is x+8

Find an expression for the length

Vol = LWH solve L

Vol / (WH) = L so

L = (x³ +11x² + 20x – 32) / (x-1) (x+8)

so it would help to factor the numerator

(x³ +11x² + 20x – 32) I'm willing to bet (x-1) and (x+8) are factors

but I will plot the equation to find the three roots

(x³ +11x² + 20x – 32) = (x-1) (x+8) (x+4)

L = (x³ +11x² + 20x – 32) / (x-1) (x+8)

= (x-1) (x+8) (x+4) / (x-1) (x+8) the (x-1) and (x+8) cancel out leaving

L = (x + 4)

7 0

3 years ago

How do I find the indicated derivative?

sergey [27]

Multiply the fraction by both things in the parenthesis.

8 0

3 years ago

A right triangle has sides of length 3, 4, and .

olchik [2.2K]

Answer:

5/hypotenuse, the square root of 7/ leg

Step-by-step explanation:

3^2+4^2=25 or 5^2. you use a^2+b^2=c^2. it would be one of the hypotenuses. If the missing number is a leg, you would do 4^2=3^2+x^2. 16=9+x^2, 7=x^2, so you plug in the numbers differently.

3 0

3 years ago

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