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makvit [3.9K]
3 years ago
12

Hello, I need help on this question.

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0
The first one should be the answer if 1-4 is prizes and 5-10 is prizes then you have to keep track of the tries it takes before you is see a 1, 2, 3, or 4.
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F(t) = t - 6<br> f(u + 6) =
vovikov84 [41]

Answer:

  f(u +6) = u

Step-by-step explanation:

Put (u+6) in place of t and simplify:

  f(u+6) = (u+6) -6

  f(u+6) = u

4 0
3 years ago
What is the vertex of the parabola?<br><br>A. (-1,0)<br>B. (0,-3)<br>C. (1,-4)<br>D. (3,0)​
katovenus [111]

d. (1,-4) is the answer

7 0
3 years ago
Read 2 more answers
HEY YOU! YEAH, YOU! WILLING TO HELP OUT A FELLOW HONORS STUDENT? IF SO, ANSWER THIS. I WILL MARK BRAINLIEST...!
Digiron [165]

Answer:

The answer is (2,1)

Step-by-step explanation:

8 0
3 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
2 years ago
Is one sixth equivalent to two twelves
VikaD [51]

Answer:

Yes.

Step-by-step explanation:

2/12 can be reduced to 1/6


Hope this helps!


Please mark me as brainliest!


~Courtney

7 0
3 years ago
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