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Ksivusya [100]
2 years ago
9

________ are neutral particles found in the nucleus of an atom.

Chemistry
2 answers:
Anni [7]2 years ago
6 0
The answer is Neutrons
IRISSAK [1]2 years ago
3 0
Neutrons is your answer my friend
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Enter your answer in the provided box. Sodium stearate (C17H35COONa) is a major component of bar soap. The Ka of the stearic aci
kogti [31]

Answer:

11.61 is the pH of 10.0 mL of a solution containing 3.96 g of sodium stearate.

Explanation:

Concentration of sodium stearate acid : c

Moles of sodium stearate = \frac{3.96 g}{306 g/mol}=0.01294 mol

Volume of the solution = 10.0 mL = 0.010 L

c=\frac{0.01294 mol}{0.010 L}=1.294 M

C_{17}H_{35}COONa\rightleftharpoons C_{17}H_{35}COO^-+Na^+

[C_{17}H_{35}COO^-]=c=1.294 M

C_{17}H_{35}COO^-+H_2O\rightleftharpoons C_{17}H_{35}COOH +OH^-

initially c

c           0    0

At equilibrium

(c-x)       x    x

Dissociation constant of an acid = K_a=1.3\times 10^{-5}

Expression of a dissociation constant of an acid is given by:  

K_a=\frac{[C_{17}H_{35}COOH][OH^-]}{[C_{17}H_{35}COO^-]}

K_a=\frac{(x)^2\times x}{(c -x)}

1.3\times 10^{-5}=\frac{x^2}{1.294-x}

Solving for x;

x = 0.0041 M

[OH^-]=0.0041 M

The pOH of the solution:

pOH=-\log[OH^-]=-\log[0.0041 M]=2.39

pH = 14 -pOH

pH = 14 - 2.39 = 11.61

11.61 is the pH of 10.0 mL of a solution containing 3.96 g of sodium stearate.

7 0
4 years ago
A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate. 2KClO3 mc019-1.jpg 2KCI + 3O2 What is the perc
Anon25 [30]
The balanced reaction is 2KClO3 --> 2KCl + 3O2
We first divide the 400.0 g KClO3 by the molar mass of 122.55 g/mol to get 3.26 mol KClO3. Next, we use the coefficients: 3.26 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 4.896 mol O2. Multiplying this by the molar mass of 32 g/mol gives 156.67 g O2.
Percent yield = 115.0 g / 156.67 g = 0.734 = 73.40%
3 0
3 years ago
ANSWER ASAPP<br> What causes the motion of particles? And more energy equals what?
STALIN [3.7K]

Answer:

particles in solids are always vibrating (moving back and forth) in place the vibrational motion of particles in solids is kinetic energy heat makes the particles in a solid vibrate faster, giving them more kinetic energy faster-vibrating particles bump into one another more often and hit each other harder

4 0
3 years ago
The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the limiti
nadezda [96]

Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass  = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈  combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%

The percentage yield = 83.77%.

7 0
3 years ago
Which of the following best describes an atom?
Tanzania [10]

Answer: The smallest unit of matter.

Explanation:

7 0
4 years ago
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