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Lostsunrise [7]
3 years ago
14

During an earthquake the cooling system of a nuclear reaction can be compromise increasing the threat of what?

Chemistry
2 answers:
ohaa [14]3 years ago
7 0

Explanation:

It can be compromise increasing the threat of a meltdown

Gnesinka [82]3 years ago
3 0

Answer: a meltdown

Explanation:

You might be interested in
The___ of an element is the number of
castortr0y [4]

Answer:atomic mass, neutrons in the nucleus

Explanation: because I remember from when I took honors chemistry last year we learned about this and it’s called the atomic mass when looking at an atom and the neutrons in the nucleus are effected by it.

8 0
2 years ago
Please help me on this I’ll give 30 points
Rufina [12.5K]

Answer:

                     1. 10.66 moles of Al

                     2.  2.5 moles of Al₂O₃

                     3. 143.87 g of SO₂

Explanation:

                    The balance chemical equation is as follow,

                                      4 Al + 3 O₂ → 2 Al₂O₃

<h3>1.</h3>

According to balance chemical equation,

                       3 moles of O₂ required  =  4 moles of Al

So,

                     8 moles of O₂ will require  =  X moles of Al

Solving for X,

                      X =  8 mol × 4 mol / 3 mol

                      X =  10.66 moles of Al

<h3>2.</h3>

According to balance chemical equation,

                       4 moles of Al produced  =  2 moles of Al₂O₃

So,

                     5 moles of Al will produce  =  X moles of Al₂O₃

Solving for X,

                      X =  5 mol × 2 mol / 4 mol

                      X =  2.5 moles of Al₂O₃

<h3>3.</h3>

The balance chemical equation for the oxidation of carbon disulfide is as follow;

                                CS₂ + 3 O₂ → CO₂ + 2 SO₂

Step 1: <u>Calculate Moles of CS₂ as;</u>

                  Moles  =  Mass / M.Mass

                  Moles  =  85.5 g / 76.14 g/mol

                  Moles  =  1.12 moles of CS₂

Step 2: <u>Find out moles of SO₂ as;</u>

According to balance chemical equation,

                       1 mole of CS₂ produced  =  2 moles of SO₂

So,

                     1.12 moles of CS₂ will produce  =  X moles of SO₂

Solving for X,

                      X =  1.12 mol × 2 mol / 1 mol

                      X =  2.24 moles of SO₂

Step 3: <u>Calculate Mass of SO₂ as;</u>

                  Mass  =  Moles × M.Mass

                  Mass  =  2.24 mol × 64.06 g/mol

                  Mass  =  143.87 g of SO₂

4 0
3 years ago
A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho
nordsb [41]

The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

<h3>What does mcg kg mean?</h3>

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

The number of mcg/kg/minute = flow rate × concentration ÷ mass of client

Flow rate = 12 ml/hour = 12 ml/hour × 1 hr/60 min = 0.2 ml/min

Concentration = mass of dopamine/volume

where

mass of dopamine = 800 mg and

volume =  500 ml

Concentration =800 mg/500 ml

= 1.6 mg/ml

= 1.6 mg/ml × 1000 mcg/mg

= 1600 mcg/ml

mass of client = 70 kg

Calculating mcg/kg/minute

So, substituting the variables into the equation, we have

mcg/kg/minute = flow rate × concentration ÷ mass of client

mcg/kg/minute = 0.08 ml/min × 1600 mcg/ml ÷ 70 kg

mcg/kg/minute = 320 mcg/min ÷ 70 kg

mcg/kg/minute = 1.904 mcg/kg/min

Thus, the mcg/kg/minute the client is receiving is 1.904 mcg/kg/min

Learn more about mcg/kg/minute here:

brainly.com/question/4253005

#SPJ1

7 0
1 year ago
(a) Compute the radius r of an impurity atom that will just fit into an FCC octahedral site in terms of the atomic radius R of t
11Alexandr11 [23.1K]

Answer:

a

The radius of an impurity atom occupying FCC octahedral site is 0.414{\rm{R}}

b

The radius of an impurity atom occupying FCC tetrahedral site is 0.225{\rm{R}} .

Explanation:

In order to get a better understanding of the solution we need to understand that the concept used to solve this question is based on the voids present in a unit cell. Looking at the fundamentals

An impurity atom in a unit cell occupies the void spaces. In FCC type of structure, there are two types of voids present. First, an octahedral void is a hole created when six spheres touch each other usually placed at the body center. On the other hand, a tetrahedral void is generated when four spheres touch each other and is placed along the body diagonal.

Step 1 of 2

(1)

The position of an atom that fits in the octahedral site with radius \left( r \right)is as shown in the first uploaded image.

In the above diagram, R is the radius of atom and a is the edge length of the unit cell.

The radius of the impurity is as follows:

2r=a-2R------(A)

The relation between radius of atom and edge length is calculated using Pythagoras Theorem is shown as follows:

Consider \Delta {\rm{XYZ}} as follows:

(XY)^ 2 =(YZ) ^2 +(XZ)^2

Substitute XY as{\rm{R}} + 2{\rm{R + R}} and {\rm{YZ}} as a and {\rm{ZX}} as a in above equation as follows:

(R+2R+R) ^2 =a ^2 +a^ 2\\16R ^2 =2a^ 2\\ a =2\sqrt{2R}

Substitute value of aa in equation (A) as follows:

r= \frac{2\sqrt{2}R -2R }{2} \\ =\sqrt{2} -1R\\ = 0.414R

The radius of an impurity atom occupying FCC octahedral site is 0.414{\rm{R}}

Note

An impure atom occupies the octahedral site, the relation between the radius of atom, edge length of unit cell and impure atom is calculated. The relation between the edge length and radius of atom is calculated using Pythagoras Theorem. This further enables in finding the radius of an impure atom.  

Step 2 of 2

(2)

The impure atom in FCC tetrahedral site is present at the body diagonal.

The position of an atom that fits in the octahedral site with radius rr is shown on the second uploaded image :

In the above diagram, R is the radius of atom and a is the edge length of the unit cell.

The body diagonal is represented by AD.

The relation between the radius of impurity, radius of atom and body diagonal is shown as follows:

AD=2R+2r----(B)

   In    \Delta {\rm{ABC}},

(AB) ^2 =(AC) ^2 +(BC) ^2

For calculation of AD, AB is determined using Pythagoras theorem.

Substitute {\rm{AC}} as a and {\rm{BC}} as a in above equation as follows:

(AB) ^2 =a ^2 +a ^2

AB= \sqrt{2a} ----(1)

Also,

AB=2R

Substitute value of 2{\rm{R}} for {\rm{AB}} in equation (1) as follows:

2R= \sqrt{2} aa = \sqrt{2} R

Therefore, the length of body diagonal is calculated using Pythagoras Theorem in \Delta {\rm{ABD}} as follows:

(AD) ^2 =(AB) ^2 +(BD)^2

Substitute {\rm{AB}} as \sqrt 2a   and {\rm{BD}} as a in above equation as follows:

(AD) ^2 =( \sqrt 2a) ^2 +(a) ^2 AD= \sqrt3a

For calculation of radius of an impure atom in FCC tetrahedral site,

Substitute value of AD in equation (B) as follows:

\sqrt 3a=2R+2r

Substitute a as \sqrt 2{\rm{R}} in above equation as follows:

( \sqrt3 )( \sqrt2 )R=2R+2r\\\\

r = \frac{2.4494R-2R}{2}\\

=0.2247R

\approx 0.225R

The radius of an impurity atom occupying FCC tetrahedral site is 0.225{\rm{R}} .

Note

An impure atom occupies the tetrahedral site, the relation between the radius of atom, edge length of unit cell and impure atom is calculated. The length of body diagonal is calculated using Pythagoras Theorem. The body diagonal is equal to the sum of the radii of two atoms. This helps in determining the relation between the radius of impure atom and radius of atom present in the unit cell.

7 0
3 years ago
Please answer fast!!! what does base stand for in science
pychu [463]
There are multiple meanings for a base. A base can be a substance that accepts hydrogen ions, or it could be something that is not acidic, in other words meaning its pH is between 7 and 14.
8 0
3 years ago
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