In a bag of m&ms, there are 12 blue,7 browns, 16 red,6 green, 4 yellow, 8 orange.What is the probability of choosing a brown
or green candy from the bag
2 answers:
Answer:
13/53
Step-by-step explanation:
Total number of m&m's = 53
Probability of choosing a brown candy = 7/53
Probability of choosing a green candy = 6/53
Probability of choosing a green or brown candy
= 7/53 + 6/53
=13/53
Answer:
40 percent
Step-by-step explanation:
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