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Alex777 [14]
3 years ago
12

In a bag of m&ms, there are 12 blue,7 browns, 16 red,6 green, 4 yellow, 8 orange.What is the probability of choosing a brown

or green candy from the bag
Mathematics
2 answers:
Deffense [45]3 years ago
8 0

Answer:

13/53

Step-by-step explanation:

Total number of m&m's = 53

Probability of choosing a brown candy = 7/53

Probability of choosing a green candy = 6/53

Probability of choosing a green or brown candy

= 7/53 + 6/53

=13/53

iris [78.8K]3 years ago
4 0

Answer:

40 percent

Step-by-step explanation:

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Aaron is using a special beaker in science that is a cylinder with a radius of 2 cm and a height of 3 cm on top of a cylinder th
Vilka [71]
Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.

We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.

Given, π = 3.14

Beaker 1:

Radius (r₁) = 2 cm
Height (h₁) = 3 cm

Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³

Beaker 2:

Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³

Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³


7 0
3 years ago
Read 2 more answers
To assess the accuracy of a laboratory scale, a standard weight that is known to weigh 1 gram is repeatedly weighed 4 times. The
zhannawk [14.2K]

Answer:

(0.9464,1.034)

Step-by-step explanation:

First find the mean μ  of all values as;

(0.95+1.02+ 1.01+ 0.98 ) /4 =0.99

μ=0.99

Find the standard deviation as;

-For each value subtract the mean and square the results

0.95-0.99 = -0.04 , -0.04² = 0.0016

1.02-0.99= 0.03, 0.03²=0.0009

1.01-0.99= 0.02, 0.02²= 0.0004

0.98-0.99 = -0.01, -0.01²=0.0001

Find mean of squared deviations as;

(0.0016+0.0009+0.0004+0.0001)/4 =0.00075 ----variance

Standard deviation = √0.00075 = 0.0274

δ = 0.0274

n=4

Thus n< 30 , confidence interval for μ = x ± t*δ/√n ---------(i)

Degree of freedom (df) = n-1 =4-1 =3

The t value for 95% confidence with df= 3 is t=3.182

Substituting the values in equation (i)

0.99 ± 3.182 * 0.0274/√4

0.99 ± 3.182 * 0.0274/2

0.99 ± 3.182 * 0.0137

0.99 ± 0.0436

(0.9464,1.034)

8 0
3 years ago
Which is an exponential decay function
Vikentia [17]

Answer:

Step-by-step explanation:

The last answer choice is the correct one.  The common ratio here is 0.7, which is between 0 and 1, an important criterion for recognizing an exponential decal function.  Every time x increases, f(x) will decrease.

4 0
3 years ago
Answer the following 3 question(s) using the information from the scenario below.
finlep [7]

Answer:

Answer 1: a. Moonlight: C=75n+1000

Riverside: C=50n+1500

Answer 2: c. The solution coordinates are c. (20, 2500)

Answer 3: c. When there are 20 guests attending the price is $2500.

Step-by-step explanation:

Moonlight Hall:

Fixed cost = $1000

Cost per guest = $75

Cost of <em>'n' </em>guests = 75 \times n

Total cost of moonlight hall = Fixed cost + Cost of 'n' guests

\Rightarrow 1000 + 75 \times n

Riverside Hall:

Fixed cost = $1500

Cost per guest = $50

Cost of <em>'n' </em>guests = 50 \times n

Total cost of moonlight hall = Fixed cost + Cost of 'n' guests

\Rightarrow 1500 + 50 \times n

Hence, Answer 1:

a. Moonlight: C=75n+1000

Riverside: C=50n+1500

Answer 2: Coordinates of solution:

Option c. (20,2500) satisfies both the equation.

When there are 20 number of guests, the cost of both moonlight and riverside hall comes out to be 2500.

Moonlight Hall cost

75 \times 20 + 1000\\\Rightarrow \$2500

Riverside Hall cost

50 \times 20 + 1500\\\Rightarrow \$2500

Answer 3: c. When there are 20 guests attending the price is $2500.

The solution is done in Answer 2.

So,

Answer 1: a. Moonlight: C=75n+1000

Riverside: C=50n+1500

Answer 2: c. The solution coordinates are c. (20, 2500)

Answer 3: c. When there are 20 guests attending the price is $2500.

6 0
3 years ago
Un boligrafo cuesta 30 ptas mas que un lapiz. Un muchacho ha comprado 8 boligrafos y 15 lapices. En total le han costado 700 pta
Firdavs [7]

Por un sistema de ecuaciones, tiene-se que:

  • Cada lapiz cuesta 20 ptas.
  • Cada boligrafo cuesta 50 ptas.

-------------------------

  • Considera-se un sistema de ecuaciones, con cada boligrafo custando x y cada lapiz custando y.
  • <u>Boligrafo cuesta 30 mas que un lapiz</u>, o sea, x = 30 + y
  • <u>8 boligrafos y 15 lapices cuesta 700</u>, o sea, 8x + 15y = 700

-------------------------

  • Aplicando el <u>primer ecuación en la segunda, </u>tiene-se el cuesto de cada lapiz:

8x + 15y = 700

8(30 + y) + 15y = 700

240 + 8y + 15y = 700

23y = 460

y = \frac{460}{23}

y = 20

Cada lapiz cuesta 20 ptas.

-------------------------

Por fin, el cuesto de cada boligrafo es dado por:

x = 30 + y = 30 + 20 = 50

Cada boligrafo cuesta 50 ptas.

Un problema similar es dado en brainly.com/question/24637096

4 0
3 years ago
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