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2 years ago

Which is a graph of y= 3x-1?

Mathematics

2 answers:

ryzh [129]2 years ago

4 0

Answer:

y=3x-1 = x=1/3

Step-by-step explanation:

y=3x-1

to find the 0-intercept at x, underline y = 0

0=3x-1

move the variable to the left side and change its sign

-3x=-1

divide both sides of the equation by -3

x=1/3

m_a_m_a [10]2 years ago

4 0

Answer: its bottom left, because look at the axis, y axis is the vertical line, check that closely :)

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Will mark brainliest for correct answer!!

SIZIF [17.4K]

Answer:

93.5

Step-by-step explanation:

trust me im a verified genius

7 0

3 years ago

35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa

Tatiana [17]

Answer:

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

$\bar X=1450$ represent the sample mean for the SAT scores

$\mu$ population mean (variable of interest)

$s^2 = 900$ represent the sample variance given

n=25 represent the sample size

Solution

The confidence interval for the true mean is given by :

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The sample deviation would be $s=\sqrt{900}= 30$

The degrees of freedom are given by:

$df=n-1=2-25=24$

The Confidence is 0.954 or 95.4%, the value of $\alpha=0.046$ and $\alpha/2 =0.023$ , assuming that we can use the normal distribution in order to find the quantile the critical value would be $z_{\alpha/2} \approx 2.0$

The confidence interval would be

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

3 0

3 years ago

Please solve in the next 10 minutes pleaseeee

Alex787 [66]

Answer:

43.82 mph

266.67 feet

Step-by-step explanation:

Given :

S = √30fl

S = speed of car

f = drag Coefficient

l = Length of skid mark

If f = 0.8 ; l = 80 feets

s = √30fl

s = √(30*0.8*80)

s = √1920

s = 43.817

s = 43.82 mph

B.)

s = 80 mph

f = 0.8

s = √30fl

80 = √30*0.8*l

80 = √24l

Square both sides

80² = 24l

6400 = 24l

l = 6400/24

l = 266.67 feets

6 0

2 years ago

The inequality 10.45b + 56.50 < 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceedin

PSYCHO15rus [73]

We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.

6 0

3 years ago

Read 2 more answers

Adam has created a register for the bank account he opened on April 16th. Unfortunately, Adam has made a mistake and cannot figu

sesenic [268]

Answer:

D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.

Step-by-step explanation:

1. Let's review the information given to us to help Adam to determine where his error is.

A. He completely forgot to include the clothes he bought from Bargains RUS. No, he didn't. It was recorded properly, including the sales tax amount.

B. He made an arithmetic error in the balance column. No he didn't, the balance was calculated correctly after each transaction.

C. He recorded one of his withdrawals in the deposit column. No, he didn't. All of the withdrawals are in the right column.

D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.

8 0

2 years ago