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beks73 [17]
3 years ago
14

Convert 500erg into joule​

Mathematics
1 answer:
Pie3 years ago
4 0

Answer:

5e-5

Step-by-step explanation:

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I need help on this pleasee and please explain​
Sophie [7]

Answer:

Undefined

Step-by-step explanation:

Use the formula y2-y1/x2-x1

3-9/-5-(-5)

-6/0

Any number with a denominator of 0 is undefined

3 0
3 years ago
What is the sum of the
saul85 [17]
Well first the formula for finding exterior angles is (n-2)180

n is the number of angles, so if u have fifteen sides you do (15-2)180

13 x 180 = 2340
8 0
4 years ago
Help, please ? Thank you so much in advance and I'd appreciate it!
Darina [25.2K]
First you calculate the area of the big rectangle (ignoring the small one the bottom):

A1 = 10 x 6 = 60.

next you calculate the small one:

A2 = 2 x 2 = 4

Now you subtract the small one from the big one and you get:

Area of the figure = A1 - A2 = 60 - 4 = 56
7 0
3 years ago
Read 2 more answers
The side of each of the equilateral triangles in the figure is twice the side of the central regular hexagon. What fraction of t
lana [24]

Answer:

The fraction is 1/4

Step-by-step explanation:

we know that

The area of an equilateral triangle, using the law of sines is equal to

A=\frac{1}{2}x^{2}sin(60^o)

A=\frac{1}{2}x^{2}(\frac{\sqrt{3}}{2})

A=x^{2}\frac{\sqrt{3}}{4}

where

x is the length side of the triangle

In this problem

Let

b ----> the length side of the regular hexagon

2b ---> the length side of the equilateral triangle

step 1

Find the area of the six triangles

Multiply the area of one triangle by 6

A=6[x^{2}\frac{\sqrt{3}}{4}]

A=3x^{2}\frac{\sqrt{3}}{2}

we have

x=2b\ units

substitute

A=3(2b)^{2}\frac{\sqrt{3}}{2}\\\\A=6b^{2}\sqrt{3}\ units^2

step 2

Find the area of the regular hexagon

Remember that, a regular hexagon can be divided into 6 equilateral triangles

so

The area of the regular hexagon is the same that the area of 6 equilateral triangles

A=3x^{2}\frac{\sqrt{3}}{2}

we have

x=b\ in

substitute

A=3(b)^{2}\frac{\sqrt{3}}{2}

step 3

To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

3(b)^{2}\frac{\sqrt{3}}{2}:6b^{2}\sqrt{3}=\frac{3}{2} :6=\frac{3}{12}=\frac{1}{4}

3 0
4 years ago
Please help and show all work.
Stels [109]
1. 73
2.40
3.78
werent too hard
4 0
3 years ago
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