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3 years ago

Part C

Mathematics

1 answer:

nika2105 [10]3 years ago

7 0

Answer:

rare llike 22%

Step-by-step explanation:

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Suppose you invest $10,410 in equipment to manufacture a new board game. Each game costs $2.65 to manufacture and sells for $20.

leva [86]

Let x= number of board games
20x=10410+2.65x 
-2.65 -2.65 
17.35x=10410 
/17.35 /17.35 
x=600 
You would need to sell at least 600 board games to break even

3 0

3 years ago

Find the area, in square inches, of the following composite figure.

Mama L [17]

I think the answer it’s 15 in not 100% sure tho

8 0

3 years ago

Line l has a slope of...

xz_007 [3.2K]

Hey there! :)

Answer:

Option C.

Step-by-step explanation:

A perpendicular line to 2/3 will be the reciprocal and negative of this fraction. Therefore:

Slope of perpendicular line = -3/2.

Remember, the equation for solving for the slope is:

$m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}$

We must find points that when plugged into this equation, equal to -3/2.

Plugging in the points in option A:

$\frac{2}{3} \neq \frac{-3}{2}$

Option B:

$\frac{3}{4} \neq \frac{-3}{2}$

Option C: This is the correct answer.

$\frac{-3}{2} = \frac{-3}{2}$

Option D:

$\frac{2}{10}\neq \frac{-3}{2}$

5 0

3 years ago

Read 2 more answers

a triangle with vertices (0 0) (5 3) (10 1) is dilated with a center of dilation at the origin by a factor of 5. what are the ne

Anastasy [175]

Algebraic rule —-> (x,y)—->(5x,5y)

(0,0) —> 0,0
(5,3)—-> 25,15
(10,1)—->50,5

6 0

4 years ago

Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu

Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

Cada manzana cuesta $3.
Cada pera cuesta $1.

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Un sistema de ecuaciones soluciona esta pergunta.
El custo de una manzana es x.
El custo de una pera es y.

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Seis manzanas y 8 peras cuestan $26, o sea, $6x + 8y = 26$
Cada manzana cuesta el triple de cada pera, o sea, $x = 3y$

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Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

$6x + 8y = 26$

$6(3y) + 8y = 26$

$18y + 8y = 26$

$26y = 26$

$y = \frac{26}{26}$

$y = 1$

Cada pera cuesta $1.

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Cada manzana cuesta el triple de cada pera, o sea, $x = 3y = 3(1) = 3$ .

Cada manzana cuesta $3.

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6 0

3 years ago