The interest rate is 4<span />
Answer:
-1.683
Step-by-step explanation:
Given :
Group 1 :
x1 = 667 ; n1 = 10 ; s1 = 20
Group 2 :
x2 = 679 ; n2 = 14 ; s2 = 15
The test statistic assuming equal variance :
x1 - x2 / √[Sp² * (1/n1 + 1/n2)]
sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)
Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59
Test statistic =
(667 - 679)/ √[296.59 * (1/10 + 1/14)]
-12 / 7.1304978
Test statistic = - 1.682
Answer:
1,007 calories in total
Step-by-step explanation:
Answer:the balance after 7 years is $3216
Step-by-step explanation:
A) Initial amount deposited into the account is $2800 This means that the principal,
P = 2800
It was compounded yearly. This means that it was compounded once in a year. So
n = 1
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for 7 years. So
t = 7
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. Therefore
A = 2800(1 + 0.04/2)^ 1× 7
A = 2800(1 + 0.02)^7
A = 2800(1.02)^7
A = $3216
Answer:
The roots are 
, which is given by option C.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question, we have that:
Which is a quadratic equation with 
. So
So the roots are , which is given by option C.
