Answer:
80 degrees
Step-by-step explanation:
The only given angle here is angle 4, which measures 100 degrees.
<u>1) Identify angle relationships</u>
Angle 4 and angle 6 are interior angles, meaning they have a sum of 180 degrees.
<u>2) Solve for angle 6</u>
180-Angle 4=Angle 6
180-100=Angle 6
80=Angle 6
Therefore, the measure of angle 6 is 80 degrees.
I hope this helps!
Answer:
The volume of the finished cylinder is 
Step-by-step explanation:
To find the volume of the finished cylinder, we have to first find the volume of the hole (with 14 cm diameter and a height of 28 cm) and subtract it from the volume of the original cylinder (with diameter of 20 cm and a height of 28 cm).
Note: The hole is also cylindrical in shape.
The volume of a cylinder is given as:

where r = radius, h = height
VOLUME OF THE HOLE
The diameter of the hole is 14 cm, hence, its radius is 7 cm (14 / 2 = 7)
Its volume is:

VOLUME OF THE ORIGINAL CYLINDER
The diameter of the cylinder is 20 cm, hence, its radius is 10 cm (20 / 2 = 10)
Its volume is:

Hence, the volume of the finished cylinder will be:

The volume of the finished cylinder is 
Answer:
The length of the third side of the triangle is 30.
Step-by-step explanation:
Here is the formula for the Pythagorean Theorem:

The hypotenuse, based on the problem, is 50. Anyways, let's get back to calculating!
We need to multiply 40 times 40 and 50 times 50.
40 times 40, or 40 squared, equals to 1600.
50 times 50, or 50 squared, equals to 2500.

Now, let's subtract. 2500 - 1600 = 900. We need to find the square root of 900--which is 30, because 30 times 30, or 30 squared, equals to 900.
Make the fractions improper to multiply.2 1/5 becomes 11/5 and 1 3/4 becomes 7/4. multiply the numerators then multiply the denominators. you get 77/20, which is simplest form. don't let teachers feed you that bs about it having to be a mixed number. an improper fraction is way more useful.
Answer:
Hence the answer is given as follows,
Step-by-step explanation:
Graph of y = f(x) given,
(a) 
(b) 
(c) 
(d) 
(e) 
(f)
{ Hole in graph}
Hence solved.