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Nat2105 [25]
3 years ago
5

A. Determine the value of each function

Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

a= -5

b=5

c=6

substitue each value as x

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maria has a total of 95 dimes and quarters. If the total value of the coins is $23.45, how many quarters does she have? Please S
NARA [144]
This is the concept of application of quadratic equations; To get the number of dimes and quarters we proceed as follows;
suppose there are x dimes and y quarters;
x+y=95.......i
but we know;
$0.1=1 dimes
$0.25=1 quarters 
thus
0.1x+0.25y=23.45.....ii
solving equation i and ii by substitution we shall have:
from i;
x=95-y
thus substituting the value of x in equation ii we get
0.1(95-y)+0.25y=23.45
9.5-0.1y+0.25y=23.45

collecting like terms we get:
0.15y=13.95
dividing both sides by 0.15 we get;
y=13.95/0.15=93
x=95-93=2
therefore we conclude that there were 2 dimes and 93 quarters

4 0
3 years ago
Tucker and Jeremy went scuba diving in the ocean together. Tucker dove to a depth of -115 feet, while
makkiz [27]
Answer= Tucker
-115 feet into the ocean is deeper than -109 feet
8 0
3 years ago
An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

8 0
3 years ago
I can’t figure this out someone please
marishachu [46]

Answer:

a^6/(b^12c^3d)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What ordered pair is a solution to this equation 4x+y=20
Ahat [919]

Answer:

happy holidays!!!!!!!! love you u are strong and a true buddy

Step-by-step explanation:

3 0
3 years ago
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