The answer is 108' because if you add 35+1 all you have to do is multiply that times 3 which is 36'×3=108'
Answer:
the rate from the plane to the radar station increasing 3 minutes later is 19.81 km/min
Step-by-step explanation:
A plane flying with a constant speed of 14 km/min passes over a ground radar station at an altitude of 4 km and climbs at an angle of 45 degrees. At what rate is the distance from the plane to the radar station increasing 3 minutes later?
speed (Δs₁)= change in distance(Δd₁) /(Δt₁)change in time
mathematically,
= Δs₁
= 14 km/min = 
and will are to find the speed after passes the radar
=Δs₂ km/min = 
to find d₁ and d₂ with respect to angle 45 degree at 4km
sin 45 = opp/hyp = 4/d₁
d₁ = 4/sin45 = 5.66km
tan 45 == opp/adj = 4/d₂
d₂ =4/tan45 = 4km
for three minute increment,
=3 x d₁ x Δs₁ = 3 x d₂ Δs₂
= 3x5.66x14 = 3x 4 xΔs₂
= 237.72 = 12Δs₂
=Δs₂ = 19.81km/min
306 / 18 = 17
So he's on $17 / hour
$204 / $17 = 12.
Therefore he'd make $204 in 12 hours.
Answer:
The line will be going 'uphill' from left to right
Step-by-step explanation:
we know that
The equation of the line into slope intercept form is equal to
y=mx+b
where m is the slope
b is the y-intercept
If the coefficient of the x-term is positive
then
the slope is positive
therefore
If the values of x increases, the values of y increases
If the values of x decreases, the values of y decreases
The line will be going 'uphill' from left to right
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