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3 years ago

What is equivalent to 6 + 3 x 9 - 4

Mathematics

1 answer:

STALIN [3.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

6 + 3 x 9 - 4

6 + 27 - 4

33 - 4

=29

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Please help! I'm having problems with deciding if 2.80 would be 2 or less or 2 or more.

Gekata [30.6K]

2.80 is more than 2, i would round it.

So sorry if this is wrong :(

7 0

3 years ago

Mr.William orders 2 feet of trim to decorate pillows. If he needs 1inch of trim for each pillow, how many pillows can he decorat

navik [9.2K]

2 feet = 24 inches

24 inches divided by 1 inch = 24

Answer is 24 pillows.

3 0

3 years ago

Eliott was trying to factor 6x^2-18 . He found that the greatest common factor of these terms was 6 and made an area model:

Semenov [28]

x²-3

Step-by-step explanation:

The expression given is;

6x²-18

Finding the greatest common factor of the terms and simplifying the expression will be;

Divide the terms by 6 to get;

x²-3

Graphing the expression to find the area model will be as attached;

Learn More

Factorizing expressions:brainly.com/question/12290978

Keywords : factor, greatest common factor, terms, area model

#LearnwithBrainly

4 0

3 years ago

A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randoml

Andrews [41]

Answer: $\dfrac{21}{410}$ .

Step-by-step explanation:

Formula : Probability = $\dfrac{\text{favorable outcomes}}{\text{Total outcomes}}$

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = $\dfrac{12}{41}$

Probability that the the second student obtained is a senior. $=\dfrac{7}{41-1}=\dfrac{7}{40}$

Then, the probability that the first student obtained is a junior and the second a senior would be $\dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}$

Hence, the required probability is $\dfrac{21}{410}$ .

8 0

3 years ago

What is the area of the region bounded between the curves y=x and y=sqrt(x)?

erastova [34]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

y = x .....(1)

$y=\sqrt{x}$ .... (2)

By solving equation (1) and equation (2)

$x = \sqrt{x}$

$\sqrt{x}\left ( \sqrt{x}-1 \right )=0$

$\sqrt{x}=0$ or $\left ( \sqrt{x}-1 \right )=0$

x = 0, x = 1

y = 0, y = 1

A = $\int_{0}^{1}ydx(curve)-\int_{0}^{1}ydx(line)$

A = $\int_{0}^{1}\sqrt{x}dx-\int_{0}^{1}xdx$

A = $\frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}$

A = $\frac{2}{3}-\frac{1}{2}$

A = $\frac{1}{6}$

8 0

3 years ago