3 years ago

The sum of cameron,karlee,and Denise age is 49. how old is each person

Mathematics

1 answer:

Arisa [49]3 years ago

3 0

Well if you divide 49 by 3 people you would get a decimal number then you round up

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HELP ME FAST PLEASE! <br>y varies directly with x, and y=2. What is the value of y when x=5?

stealth61 [152]

my answer would be 10, but I might be wrong

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3 years ago

Divide and simplify

slamgirl [31]

Answer:

7/9y+441/567

Step-by-step explanation:

y^2-49/81y+567÷y-7/63

=y^2-49/81y+567×63/y-7

=(y-7)(y+7)/81y+567×63/y-7

=(y+7)×63/81y+567

=63y+441/81y+567

=7/9y+441/567

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4 years ago

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Dennis_Churaev [7]

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3 years ago

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4 years ago

Given that log_{a}(3) = 0.477 and

kipiarov [429]

Given:

$\log_{a}(3) = 0.477,\log_{a}(5) = 0.699$

To find:

The value of $\log_{a}(0.6)$ .

Solution:

We need to find the value of:

$\log_{a}(0.6)$

It can be written as

$\log_{a}(0.6)=\log_a\left(\dfrac{6}{10}\right)$

$\log_{a}(0.6)=\log_a\left(\dfrac{3}{5}\right)$

By using the property of logarithm, we get

$\log_{a}(0.6)=\log_a(3)-\log_a(5)$ $[\because \log \dfrac{a}{b}=\log a-\log b]$

$\log_{a}(0.6)=\log_a(3)-\log_a(5)$

On substituting the given values, we get

$\log_{a}(0.6)=0.477-0.699$

$\log_{a}(0.6)=-0.222$

Therefore, the values of $\log_a(0.6)$ is -0.222.

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3 years ago