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ehidna [41]
2 years ago
5

An electronic element that stores data by changing its resistance based on the current that has passed through it (similar to RR

AM) is called a(n) ___ .
Computers and Technology
1 answer:
maksim [4K]2 years ago
4 0
Computer data storage
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the easiest and cheapest time to alter the information system is in the ________ phase of the sdlc. a. requirements analysis b.
nignag [31]
I would think its the "<span>requirements analysis" phase.

Because the </span>requirements analysis<span>,</span><span> is the process of determining user expectations for a new or modified product.</span>
7 0
3 years ago
My mom hid my laptop and now I can't find it​
Svetach [21]

Answer: did you look everywhere ask for it and be like mom i wont do (whatever you did) ever again so please give me a chance can i plsss!!!!!! have it back?

Explanation:

simple as that step by step

3 0
2 years ago
Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

5 0
3 years ago
Write a code snippet Now write your own code snippet that asks the user to enter two numbers of integer type (one at a time) and
taurus [48]

Explanation:

num1= print("Enter a number :")

num2 = print("Enter a number :")

sum = num1 + num2

print(sum)

4 0
2 years ago
If a firm is set to use open-source software with which no one in the IT department is familiar, what should it do? fire the IT
Aleonysh [2.5K]
The most efficient thing to do would be to provide training as firing or doing nothing halts productivity indefinitely while training eventually will finish
7 0
3 years ago
Read 2 more answers
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