Question

25 POINTS! Which equation is equivalent to (1/3)=27^x^+^2

Answer 1

Answer:

match bases

remeber if a^b=a^c where a=a then b=c

remember

(x^m)^n=x^(mn)

1/(x^m)=x^-m

base of 3

(1/3)^x=(3^-1)^x=3^(-x)

27^(x+2)=(3^3)^(x+2)=3^(3x+6)

3^(-x)=3^(3x+6)

-x=3x+6

0=4x+6

-6=4x

-3/2=x

Answer 2

Hint:     $\bf log_{{ a}}{{ b}}=y \iff {{ a}}^y={{ b}}$