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andrew-mc [135]
3 years ago
5

I need help quick please!

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

taking that blank as x

8*13=8x+8*6

104=8x+48

104-48=8x

56=8x

x=7

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Round 1.7802 to 1 significant figure
tiny-mole [99]

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It would be 2

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Based on this report, you can conclude that a total of ___11__ individuals participated in the research study .

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Given that a  research report describing the results from a repeated-measures study states:

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A study by Consumer Reports showed that 64% of supermarket shoppers believe supermarket brands to be as good as national name br
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Answer:

Step-by-step explanation:

Given that:

A study is conducted and the study by Consumer Reports showed that 64% of supermarket shoppers believe supermarket brands to be as good as national name brands.

a)

Thus; we formulate the null and the alternative hypotheses as follows:

The proportion is ; \frac{64}{100} = 0.64

Null hypothesis:    {H_0}:p = 0.64  

The Null hypothesis states that there is no evidence that “the percentage of supermarket shoppers believes that the supermarket ketchup is good as the national brand ketchup differ form 64%”.

Alternative hypothesis: {H_a}:p \ne 0.64H

The Alternative hypothesis states that there is evidence that “the percentage of supermarket shoppers believes that the supermarket ketchup is good as the national brand ketchup differ form 64%”.

b)

The proportion of the population = 0.64

The sample size n = 100

The number of shoppers = 52  stating that the supermarket brand was as good as the national brand

The sample proportion \hat  p = \frac{52}{100}

\hat  p = 0.52

The z - value is calculated by the formula:

z = \dfrac{\hat p-p}{\frac{\sqrt{ p(1-p)}}{100 }}

z = \dfrac{0.52-0.64}{\frac{\sqrt{ 0.64(1-0.64)}}{100 }}

z = \dfrac{-0.12}{0.048 }}

z = -2.50

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the p-value = 2P(Z ≤ -2.50)

p-value = 2 × 0.0062

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c)

At  significance level,  ∝ = 0.05 ; The p-value = 0.0124

According to  the rejection rule, if p-value is less than 0.05 then we will reject null hypothesis at ∝ = 0.05

Hence, the p-value =0.0124 < ∝ (=0.05)

According to the reject rule; reject null hypothesis.

Conclusion: There is no evidence at all that the percentage of supermarket shoppers believes that the supermarket ketchup is good as the national brand ketchup differ form 64%.

d) we know that the significance level of ∝  = 0.05

The value{z__{0.05}}  is obtained as:

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Conclusion:

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Therefore, Yes, the national brand ketchup manufacturer is pleased with the conclusion.

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