<span>not true
answer is
</span><span>x^5y^5z^5 = xyz^5
should be
(xyz)^5</span>
Answer:
x has infinite solutions
Step-by-step explanation:
|4x−4(x+1)|=4
Simplify inside the absolute value by distributing the 4
|4x−4x+4|=4
Combine like terms
|4|=4
The absolute value of 4 is 4
4=4
This is always true, so x is all real values
x has infinite solutions
(3x-4y)^2=9x^2-24x+16y^2
(3x-2)(9x^2+6x+4)=27x^3-8
X(5x+9)
x appears in both terms, so you can take it out
