Answer:
Problem 1. <em>(19/2)b + 15</em>
Problem 2. <em>3/16</em>
Step-by-step explanation:
Question number 1
5/8 (16b+24) -1/2b =
= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b
= 10b + 15 - (1/2)b
= (20/2)b - (1/2)b + 15
= (19/2)b + 15
Question number 2
3/4 (16/64 + 12a) -9a =
= (3/4) * (16/64) + (3/4) * 12a - 9a
= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a
= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a
= 3/16 + (3 * 3)/(1 * 1) * a - 9a
= 3/16 + 9a - 9a
= 3/16
Answer:
A nothing
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Required
The volume of the remaining cylinder
Before the cut-out, the cylinder has a volume (V) of:
After the cut-out, the cylinder has a volume of:
![V = \pi [R^2 -r^2]h](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%5BR%5E2%20-r%5E2%5Dh)
So, we have:
![V = 3.14* [6^2 -5^2]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B6%5E2%20-5%5E2%5D%2A15)
![V = 3.14* [36 -25]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B36%20-25%5D%2A15)
Answer:
pee
Step-by-step explanation:
i think its a carrot
