Given that the arc length is 4.189 cm and the radius is 3 cm, the size of the arc will found as follows;
C=theta/360 πd
suppose:
size of arc=theta=x
d=3*2=6 cm
hence;
4.189=x/360*π*6
4.189=0.0524x
x=4.189/0.0524
x=80.004°
The size of the arc length is 80.004°
Maya can get 3 cups of ice cream with 1/3 of a cup left over I hope this helped
Answer:
Explanation:Since, you have not included the formula, I will work here with the formula for
constant accelaration motion that relates the four variables:
displacement (d), Vo (initial velocity), a (acceleration) and t (time).1)
displacement formula:

2) Subtract the term Vot from both sides:

3) Multiply both sides by 2:

4) Divide both sides by t²
![2[d-V_0t]/t^2=a](https://tex.z-dn.net/?f=2%5Bd-V_0t%5D%2Ft%5E2%3Da)
So, you have obtainded:
a = 2[d - Vo×t] / t²Yet, you can arrange it in different ways. For example, you might separate into two terms:
Answer:
the answer is 3
Step-by-step explanation:
N = 3
I believe it would be 4y-9