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liberstina [14]
3 years ago
12

For the rectangle provided, the length of this rectangle is 5 mm longer than its width. The perimeter of this rectangle is more

than 42 mm. Let w equal the width of the rectangle.
A) Define the length of the rectangle in terms of w (the width).

B) Use the expressions to write an inequality based on the given information.

C) Solve the inequality, clearly indicating the width of the rectangle.
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
A) length= w+5
width=w
perimeter=42mm
B) 2(w+5)+2w>42
2w+10+2w>42
4w>32
w>8
The width should be greater than 8 and the length should be more than 13.

Hope this helps!
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If you are driving 20 meters per second, what would be the equivalent of that in miles per hour?
melomori [17]

\frac{20 meters}{1 second}  \frac{60 seconds}{1 minute}  \frac{60 minutes}{1 hour}

the fractions are set up so that each unit cancels out until its only meters/hour

you can multiply all the numerators together to get 72000 and all the denominators to get 1

72000 meters/1 hour

72000 meters in 1 hour

hope this helped

8 0
3 years ago
(Refer to the attached image)​
DENIUS [597]
<h3>Answer:  9 meters</h3>

===========================================

Work Shown:

  • side a = 8
  • side b = 5
  • angle C = 88 degrees

Applying the law of cosines

c^2 = a^2 + b^2 - 2*a*b*cos(C)

c^2 = 8^2 + 5^2 - 2*8*5*cos(88)

c^2 = 64 + 25 - 80*cos(88)

c^2 = 86.2080403

c = sqrt(86.2080403)

c = 9.2848285

c = 9

Technically he needs 10 meters of rope because of the extra 0.28 portion, but I'll stick with 9 meters since your teacher said to round to the nearest whole number.

5 0
1 year ago
Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20
vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of y=f(x) is a vertical has an asymptote at x=a if at least one of the following statements is true:

1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty

The function is:

f(x)=\frac{x^2+7x+10}{x^2+9x+20}

First of all, let't factor out:

f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq  5

From here:

\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty

\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty

Accordingly:

x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0
3 years ago
NEED HELP I WILL BE GIVING BRAINLIEST:)
bonufazy [111]

Answer:

mathematics

Step-by-step explanation:

8 0
2 years ago
I need to know the answer
Bezzdna [24]
I think the answer is (3,5).
7 0
3 years ago
Read 2 more answers
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